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VladimirAG [237]
3 years ago
8

4. Which activity would be BEST for prolonged training within your target heart rate zone?

Physics
1 answer:
valina [46]3 years ago
6 0
I am sorry I would answer this questions but I don’t have the options of the heart rates so I can give you the best answer
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State Pascal's principle of transmission of pressure​
bulgar [2K]

Answer:

Pascal's law (also Pascal's principle or the principle of transmission of fluid-pressure) is a principle in fluid mechanics given by Blaise Pascal that states that a pressure change at any point in a confined incompressible fluid is transmitted throughout the fluid such that the same change occurs everywhere.

4 0
3 years ago
Help me plssss <br> 30 pointsssssss
labwork [276]

Answer:

d

Explanation:

6 0
3 years ago
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A 10 kg box hangs from a rope. What is the tension in the rope (in Newtons) if the box is stationary
Archy [21]

Answer:

T = 98 N

Explanation:

The gravity of the earth is known to be 9.8 m/s²

Data:

  • m = 10 kg
  • g = 9.8 m/s²
  • T = ?

Use formula:

  • \boxed{\bold{T=m*g}}

Replace and solve:

  • \boxed{\bold{T=10\ kg*9.8\frac{m}{s^{2}}}}
  • \boxed{\boxed{\bold{T=98\ N}}}

The tension in the rope is <u>98 Newtons.</u>

Greetings.

5 0
2 years ago
In chemistry, potential energy is usually considered to be the energy _____________.
Lunna [17]

Answer:

The answer is option D. Stored in the chemical bonds.

Hope it helps............

4 0
2 years ago
olivia is taking pictures of the ocean on the edge of a cliff when she accidentally drops her phone. The phone hits the water at
In-s [12.5K]

The cliff is 12.71m tall.

Why?

Before solving the problem, we must remember that the phone was dropped, it means that there is no initial velocity, also, the acceleration acting on the phone is the acceleration due to gravity.

So, to find how tall is the cliff, we can use the following equations:

y=y_o+v_o*t-\frac{1}{2}g*t^{2}\\\\v_f=v_o+g*t

t=\frac{v_f}{g} \\\\t=\frac{-15.75\frac{m}{s}}{-9.81\frac{m}{s^{2}}}=1.61s

Now that we know the time, we can calculate how tall is the cliff:

y=y_o+v_o*t+\frac{1}{2}g*t^{2}\\\\y=0+0*1.61s-\frac{1}{2}*(-9.81\frac{m}{s^{2}})*(1.61s)^{2}\\\\y=12.71m

Hence, we have that the cliff is 12.71m tall.

Have a nice day!

3 0
3 years ago
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