Answer:
The mass of copper that was heated is 30 g
Explanation:
The formula for the heat supplied, ΔH is;
ΔH = m·c·Δt
Where:
ΔH = Heat supplied = 480 J
m = Mass of the copper sample = Required
c = Specific heat capacity of copper = 0.4 J/(g·°C)
Δt = Change in temperature = T₂ - T₁ = 60° - 20° = 40°C
T₁ = Initial temperature = 20°C
T₂ = Final temperature = 60°C
Therefore, plugging the values, we have;
480 = m×0.4×40
m = 480/(0.4 × 40) = 30 g
The mass of copper that was heated = 30 g.
