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Hoochie [10]
3 years ago
14

Choose the scenario in which the sound frequency of the waves is higher.

Physics
1 answer:
mrs_skeptik [129]3 years ago
5 0

Answer:

B) the sound source moves towards you at 100 m/sec

Explanation:

The Dopper Effect is a phenomenon that occur when there is relative motion between an observer and a source of a wave. When this situation occurs, there is an apparent shift in frequency of the wave, as observed by the observer.

The apparent frequency observed by the observer is given by

f'=\frac{v\pm v_o}{v\pm v_s}f

where

f is the original frequency of the wave

f' is the apparent frequency

v is the speed of the wave

v_o is the velocity of the observer (positive if moving towards the source of the wave, negative otherwise)

v_s is the velocity of the source (negative if moving towards from the observer, positive otherwise)

In this problem, we want to find the scenario in which the sound frequency is higher.

We see that in all 4 scenarios, the sound source is moving: this means we have to find the scenario in which the denominator of the equation is smaller.

First of all, we notice the sound source moves towards the observer, v_s is negative, so the denominator is higher: this means that the correct option must be either A or B.

Also, we notice that since v_s is negative, a value larger in magnitude will mean a smaller denominator: therefore, the correct answer will be

B) the sound source moves towards you at 100 m/sec

Since this situation will make the denominator of the formula the smallest possible.

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jok3333 [9.3K]

a.) K 2=K 1 +GmM( r 21− r 11)=2.2×10 7J

b.) ​K 2 +GmM( r 11− r 21)=6.9×10 7 J

Applying Law of  Energy conservation :

K 1+U 1

=K 2+U 2

⇒K 1− r 1GmM

=K 2− r 2 GmM

where M=5.0×10 23kg,r1

=> R=3.0×10 6m and m=10kg

(a) If K 1​

=5.0×10 7J and r 2

=4.0×10 6 m, then the above equation leads to

K 2=K 1 +GmM (r 21− r 11)=2.2×10 7J

(b) In this case, we require K 2

=0 and r2

=8.0×10 6m, and solve for K 1:K 1

​=K 2 +GmM (r 11− r 21)=6.9×10 7 J

Learn more about Kinetic energy on:

brainly.com/question/12337396

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7 0
2 years ago
Which statement explains why a chemical equation must be balanced?
Katena32 [7]
The answer to this question is b
7 0
3 years ago
Read 2 more answers
A swan on a lake gets airborne by flapping its wings and running on top of the water. If the swan must reach a velocity of 6.00
ira [324]

Answer:

A. 51.42 m.

B. 17.14 s.

Explanation:

Using equations of motion:

vf^2 = vi^2 + 2 * aS

Where,

vf = final velocity

a = acceleration

S = distance to which swan traveled

vi = 0 m/s

6.00^2 = 2 * 0.350S

S = 36/0.7

= 51.42 m.

B.

vf = vi + at

6 = 0 + 0.35t

t = 6/0.35

= 17.14 s.

5 0
3 years ago
A heat engine with 0.500 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 700 K . The gas goes through the fo
Zarrin [17]

Answer:

2234.63

Explanation:

Work done per cycle by the engine is calculated as;

W=\int p \ dv

#Since volume doesn't change in the isochoric steps, there is no work done, hence:

W_2=W_3=0

#For an isothermal change of state(ideal gas):

pV=nRT\\\\W=P_iV_ i\int \frac{1}{V} \ dV\\\\=P_iV_ iIn(V_f/V_i)

#for the expansion process:

W_i=0.5mol\times8.3145J/molK\times 700K \ In(6000cm^3/1000cm^3)\\\\W_i=5214.15J

W_4=0.5mol\times8.3145J/molK\times 400K \ In(6000cm^3/1000cm^3)\\\\W_4=-2979.52

W=W_1+W_2+W_3+W_4\\\\=5214.15J-2979.52\\\\=2234.63J

Hence, the engine does 2234.63J per second.

8 0
4 years ago
Can someone help pls!!
stiks02 [169]

Answer:

Rp = 10 Ohms; I = 0.9 Amps

Explanation:

Since, there are two resistors each with 20Ω connected in parallel, the total resistance of the combination (Rp) of the circuit is as follows:

i.e 1/Rp = (1/R1 + 1/R2)

1/Rp = (1/20Ω + 1/20Ω)

1/Rp = (1 + 1)/20Ω

1/Rp = 2/20Ω

1/Rp = 1/10Ω

To get the value of Rp, cross multiply

Rp x 1 = 10Ω x 1

Rp = 10Ω

Apply the formula

Voltage V = Current I x Total resistance Rp

I = V/Rp

I = 9V/10Ω

I = 0.9 Amps

Thus, the total resistance is 10 Ohms, the current through the ammeter is 0.9 Amps

8 0
3 years ago
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