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3 years ago

Which of the following occurs during th e ecological succession of an ecosystem

Biology

1 answer:

Jlenok [28]3 years ago

6 0

Living organisms modify their environment a little at a time

As an ecosystem progresses, the organisms in that ecosystem change their environment to best meet their needs, but they only do it in small ways which can make big changes over time.

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Karo-lina-s [1.5K]

I believe it's feeding relationships between different organisms

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3 years ago

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3 years ago

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Liula [17]

Answer:

A does dissolve in a greater degree as the temperature increases. B does not dissolve up to 80 degrees.

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3 years ago

Most black bears (Ursus americanus) are black or brown in color. However, occasional white bears of this species appear in some

Sphinxa [80]

Answer and Explanation:

The number of observed individuals:

AA 42

AG 24

GG 21

Total number of individuals, N= 87 = 42 + 24 + 21

Allelic frequencies:

f(p) = (2 x AA + AG)/ 2 x N

f (p)= (2 x 42 + 24) /2 x 87

f (p) = (84 + 24) / 174

f (p)= 108 / 174

f (p) = 0.62

f (q) = (2 x GG + AG)/2 x N

f (q) = (2 x 21 + 24 )/2 x 87

f (q) = (42 + 24)/ 174

f (q) = 66/174

f (q) = 0.38

p + q = 1

0.62 + 0.38 = 1

The expected genotypic frequency:

F (AA)= 0.62 ² = 0.3844

F (AG) = 2 x A x G = 2 x 0.62 x 0.38 = 0.4712

F (GG) = 0.38 ² = 0.1444

AA + AG + GG = 0.3844 + 0.4712 + 0.1444 = 1

The number of expected individuals:

AA= (0.62)² x 87 = 0.3844 x 87 = 33.44

AG= (0.4712) x 87 = 40.99

GG= (0.38)² x 87 = 12.563

Total number of expected individuals = 33.44 + 40.99 + 12.563 = 87

Chi square= sum (O-E)²/E

AA= (O-E)² /E

AA=(42 - 33.44) ² / 33.44

AA= 2.2

AB= (O-E)² /E

AB= (24 - 40.99)²/ 40.99

AB=7.04

BB=(O-E)² /E

BB= (21-12.563)²/12.563

BB= 5.66

Chi square= sum ((O-E)²/E) = 2.2 + 7.04 + 5.66 = 14.9

Degrees of freedom = genotypes - alleles = 3 - 1 = 2

p value less than 0.05

There is enough evidence to reject the nule hypothesis. The genotype frequencies are not in equilibrium.

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4 years ago

A milk snake looks similar to the deadly coral snake. This is an example of A) warning coloration adaptive radiation B) cryptic

Damm [24]

In this case, c) mimicry is the answer. In Batesian mimicry in which harmless animals mimic toxic animals. In this case, I assume the milk snake is harmless and the coral snake is venomous. Since the milk snake has a trait similar to deadly coral snake, less animals would eat it thinking it is dangerous. Over time all the milk snake that look like the deadly coral snake would survive leading to evolution by natural selection. This would lead to more and more milk snake mimicking the resemblance of the deadly coral snake.

a) The deadly coral snake has a warning color adaptive radiation. If the question had described the environment and how the snaked adapted to the environment via warning coloration. This would've been correct.

b) cryptic coloration is more about camouflage with the environment. If the question had state how a certain feature help one of the animals blend into the background. This would've been correct.

d) I'm not sure whats different between this and a so i'll consider them both the same.

3 0

3 years ago