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Vedmedyk [2.9K]
3 years ago
14

The expression once The left side of an equation is shown below. 3(x+1)+9 if the equation has no solution which expression can b

e written in the box on the other side of the equation
A. 3(x+4)
B. 2(x+6)+x
C. 4(x-3)-x
D. 3(x+1)+9
Mathematics
2 answers:
lys-0071 [83]3 years ago
7 0
<h3>Answer:</h3>

C. 4(x-3)-x

<h3>Step-by-step explanation:</h3>

All of the given expressions are equivalent to 3x+12 except selection C. Using that in your equation makes it be ...

... 3(x +1) +9 = 4(x -3) -x

... 3x +12 = 3x -12

... 12 = -12 . . . . . <em>false</em>

There is no value of x that will make this true, hence NO SOLUTION.

_____

<em>Comment on the other choices</em>

3x+12 = 3x+12 has an <em>infinite number of solutions</em>, as <u><em>any</em></u> value of x will make this true.

IgorLugansk [536]3 years ago
5 0

Answer:

C

Step-by-step explanation:

i took the test lol

>w<

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Find a power series representation for the function and determine the interval of convergence ln(5 - x
Andrew [12]
To find the power series representation of In(5 - x), we recall that the power series representation of a function of the form:
\frac{a}{1-r} =\sum\limits^\infty_{n=0}ar^n
provided |r| < 1
Also recall that
\int{\frac{a}{1-r}\,dx} =\int{\sum\limits^\infty_{n=0}ar^n\,dx}
Notice that
\ln{(5-x)}=-\int {\frac{1}{5-x}\,dx}
To get the power series of
\frac{1}{5-x}= (\frac{1}{5})  \frac{1}{1- \frac{x}{5} }  \\ =\sum\limits^\infty_{n=0}( \frac{1}{5}) (\frac{x}{5})^n=(\frac{1}{5}) (\frac{x}{5})+(\frac{1}{5}) (\frac{x^2}{25})+(\frac{1}{5}) (\frac{x^3}{125})+ . . . \\ =\frac{x}{25}+\frac{x^2}{125}+ \frac{x^3}{625}+ . . .
Therefore, the power series representation of
\ln{(5-x)}=-\int {\frac{1}{5-x}\,dx} \\ =-\int{(\frac{x}{25}+\frac{x^2}{125}+ \frac{x^3}{625}+ . . . ),dx} \\ =C-\frac{x^2}{50}-\frac{x^3}{375}- \frac{x^4}{2500}- . . .
When x = 0: C = ln 5
Therefore,
\ln{(5-x)}=\ln{5}-\frac{x^2}{50}-\frac{x^3}{375}- \frac{x^4}{2500}- . . .

The radius of convergence is given by |r| < 1.
Here,
r= \frac{x}{5}
Therefore, radius of convergence is
| \frac{x}{5}| \ \textless \ 1 \\ |x|\ \textless \ 5
4 0
3 years ago
Give me the full working and I give you stars ​
kari74 [83]

→ Area of rectangle = Length * Width

Here given:

  • Length = 63 m
  • Width = 17 m

Here area:

  • L * W
  • 63 * 17
  • 1071 m²
4 0
2 years ago
Read 2 more answers
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