The answer is B. Take the square root of both the numerator and denominator of a fraction.
First, let's break the worded equation up into two parts:
- "<span>4 times a number less than 6'
This is 4 * (6-x)
- "</span><span>8 more than twice that number"
This is 2x+8
Now combine these two expressions:
</span>4 * (6-x) = 2x+8
4 * (6-x) = 2 * (x+4)
2 * (6-x) = x+4
12-2x = x+4
-3x = -8
x = 8/3
If you have any questions, please leave it in the comment section below.
Hope this helps!
Y = |x| = x if x ≥ 0, -x if x < 0
absolute value can be interpreted as a function that does not allow negative real numbers, forcing them to be positive (leaving 0 alone). if the input x is more than or equal 0, then x stays positive so there is no need to do anything: "x if x ≥ 0".
if the input is less than 0, then it is an negative number and needs a negative coefficient to negate the negative: "-x if x < 0"
example: if x = -3, then it will take the "-x if x < 0" piece resulting in y = -(-3) = 3, which is what |-3| does
if x = 1, it will take the "x if x ≥ 0" piece and just have y = 1 which is what |1| does.
for x = 0, it will take the "x if x ≥ 0" and just have y = 0 which is what |0| does
