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dexar [7]
3 years ago
10

Which statement about gravity is true?

Chemistry
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

statement about property is not true

Explanation:

if you think the answer is Grace Mark me as brain a list

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How many moles is 17.6 g NaOH?
Lynna [10]

Answer:

\boxed {\boxed {\sf D. 0.440 \ mol \ NaOH}}

Explanation:

To convert from moles to grams, the molar mass is used (mass of 1 mole). The values are the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units.

<h3>1. Molar Mass</h3>

We are given the compound sodium hydroxide (NaOH) and we need to look up the molar masses of the individual elements.

  • Na:  22.9897693 g/mol
  • O: 15.999 g/mol
  • H: 1.008 g/mol

The formula for the compound has no subscripts, so there is 1 mole of each element in 1 mole of the substance. We can simply add the molar masses.

  • NaOH: 22.9897693 + 15.999 + 1.008 = 39.9967693 g/mol

This means there are 39.9967693 grams of sodium hydroxide in 1 mole.

<h3>2. Convert Grams to Moles </h3>

Use the molar mass we found as a ratio.

\frac {39.9967693 \ g \ NaOH}{ 1 \ mol \ NaOH}

Since we are converting 17.6 grams of NaOH to moles, we multiply by this value.

17.6 \ g\ NaOH *\frac {39.9967693 \ g \ NaOH}{ 1 \ mol \ NaOH}

Flip the ratio so the units of grams of NaOH cancel.

17.6 \ g\ NaOH *\frac {1 \ mol \ NaOH}{ 39.9967693 \ g \ NaOH}

17.6 *\frac {1 \ mol \ NaOH}{ 39.9967693}

\frac{17.6 }{ 39.9967693} \ mol \ NaOH

0.4400355406 \ mol \ NaOH

<h3>3. Round </h3>

The original measurement of grams has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

  • 0.4400355406

The 0 in the ten thousandths place (in bold above) tells us to leave the 0 in the thousandth place.

0.440 \ mol \ NaOH

17.6 grams of sodium hydroxide are equal to <u>0.440 moles of sodium hydroxide.</u>

3 0
2 years ago
Elements in a group have the same number of valence electrons and the same ____
frozen [14]
The elements in each group have the same number of electrons in the outer orbital<span>. Those </span>outer<span> electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements. Every element in the first column (group one) has one electron in its </span>outer<span> shell.</span>
5 0
2 years ago
In the first step of the reaction, which compound is the limiting reagent: sodium hydroxide or the nucleophile
anastassius [24]
Since the nucleophile is the actual attacking molecule or molecule that starts the reaction and allows for further steps in the mechanism to occur, it is the limiting reagent, as based on the amount of the nucleophile you have, the reaction will tend to proceed until you run out. The excess would be the sodium hydroxide, it is union part of the solution.
5 0
3 years ago
What is this answer <br><br> Most energy enter the ecosystem​ through the process of
max2010maxim [7]
Also, remember, light energy (from the sun) is a reactant for photosynthesis. The plant uses water sunlight and carbon dioxide to make sugars as well as oxygen. Plants, the organisms that carry out photosynthesis, are typically the first ate organism is a Food chain and so most other organisms energy came from the plant somehow. But the plant got its energy from the sun.
6 0
2 years ago
Cylinder of air at 1.5 atm of pressure is kept at room temperature while a piston compresses the air from 40 l down to 10 ml. wh
djyliett [7]

The new pressure, P₂ is 6000 atm.

<h3>Calculation:</h3>

Given,

P₁ = 1.5 atm

V₁ = 40 L = 40,000 mL

V₂ = 10 mL

To calculate,

P₂ =?

Boyle's law is applied here.

According to Boyle's law, at constant temperature, a gas's volume changes inversely with applied pressure.

                                        PV = constant

Therefore,

P₁V₁ = P₂V₂

Put the above values in the equation,

1.5 × 40,000 = P₂ × 10

P₂  = 1.5 × 4000

P₂  = 6000 atm

Therefore, the new pressure, P₂ is 6000 atm.

Learn more about Boyle's law here:

brainly.com/question/23715689

#SPJ4

8 0
2 years ago
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