Answer:
29260J
Explanation:
Given parameters:
Mass of water sample = 100g
Initial temperature = 30°C
Final temperature = 100°C
Unknown:
Energy required for the temperature change = ?
Solution:
The amount of heat required for this temperature change can be derived from the expression below;
H = m c (ΔT)
H is the amount of heat energy
m is the mass
c is the specific heat capacity of water = 4.18J/g°C
ΔT is the change in temperature
Now insert the parameters and solve;
H = 100 x 4.18 x (100 - 30)
H = 100 x 4.18 x 70 = 29260J
It is know as the normal force.
When a solid is placed on a support, the latter exerts forces on the solid at each point of contact. These are forces that oppose the weight and prevent an object from falling.
This force is usually vertical and upward and often offsets the weight. If the solid is in equilibrium on the support the forces compensate the weight of the solid.
Balanced Half reactions are:
At anode 2
==> Cl₂+
+ H₂O ==>
+ 2
+
At Cathode: 2
+
==> H₂
Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O,
,
and 
Now at Anode reaction will occur as given:
2
==> Cl₂+
+ H₂O ==>
+ 2
+
(will occur)
At Cathode:
2
+
==> H₂ (will occur)
At Cathode:
+
==> Mn (This reaction will not occur)
The deposition of solid Mn will not occur because in aqueous solution,
will be reduced before
.
The reduction potentials for
is zero whereas reduction potential for
is - 1.18V.
The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.
To learn more about the half reaction please click on the link brainly.com/question/13186640
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Answer:
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