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Nat2105 [25]
3 years ago
9

Estimate the surface-to-volume ratio of a C60 fullerene by treating the molecule as a hollow sphere and using 77pm for the atomi

c radius of carbon.
Chemistry
1 answer:
AleksAgata [21]3 years ago
7 0

Answer:

The surface-to-volume ratio of a C-60 fullerene is 3:77.

Explanation:

Surface area of sphere = S=4\pi r^2

Volume of the sphere = V=\frac{4}{3}\pi r^3

where : r  = radius of the sphere

Radius of the C-60 fullerene sphere = r = 77 pm

Surface area of the C-60 fullerene = S=4\pi (77 pm)^2...[1]

Volume area of the C-60 fullerene = V=\frac{4}{3}\pi (77 pm)^3..[2]

Dividing [1] by [2]:

\frac{S}{V}=\frac{4\pi (77 pm)^2}{\frac{4}{3}\pi (77 pm)^3}

=\frac{3}{77}

The surface-to-volume ratio of a C-60 fullerene is 3:77.

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inessss [21]

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Question: What is the formula of zinc sulphate?

Answer: The formula of zinc sulphate is ZnSO4. It contains one atom of zinc one atom of sulphur and four atom of Oxygen. It is colourless compound. It is an acidic salt which is formed by the reaction of Zinc Hydroxide and Sulphuric acid. It turns blue litmus paper into red which proves that it is acidic in nature.

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6 0
3 years ago
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If you had 24 moles of hydrogen gas how many moles of ammonia (NH3) would be produced?
dedylja [7]

Answer:

8

Explanation:

You are going to divide the 24 moles of H by the moles of H used in Ammonia. In this case 3

24/3=8

8 0
3 years ago
An aqueous potassium carbonate solution is made by dissolving 5.51 moles of K 2 CO 3 in sufficient water so that the final volum
ad-work [718]

Answer:

1.67mol/L

Explanation:

Data obtained from the question include:

Mole of solute (K2CO3) = 5.51 moles

Volume of solution = 3.30 L

Molarity =?

Molarity is simply the mole of solute per unit litre of the solution. It can be expressed mathematically as:

Molarity = mole of solute /Volume of solution

Molarity = 5.51 mol/3.30 L

Molarity = 1.67mol/L

Therefore, the molarity of K2CO3 is 1.67mol/L

3 0
3 years ago
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I NEED HELP ASAP! PLEASE BE GENUINE
love history [14]

1. The molar mass of the unknown gas obtained is 0.096 g/mol

2. The pressure of the oxygen gas in the tank is 1.524 atm

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>1. How to determine the molar mass of the gas </h3>
  • Rate of unknown gas (R₁) = 11.1 mins
  • Rate of H₂ (R₂) = 2.42 mins
  • Molar mass of H₂ (M₂) = 2.02 g/mol
  • Molar mass of unknown gas (M₁) =?

R₁/R₂ = √(M₂/M₁)

11.1 / 2.42 = √(2.02 / M₁)

Square both side

(11.1 / 2.42)² = 2.02 / M₁

Cross multiply

(11.1 / 2.42)² × M₁ = 2.02

Divide both side by (11.1 / 2.42)²

M₁ = 2.02 / (11.1 / 2.42)²

M₁ = 0.096 g/mol

<h3>2. How to determine the pressure of O₂</h3>

From the question given above, the following data were obtained:

  • Volume (V) = 438 L
  • Mass of O₂ = 0.885 kg = 885 g
  • Molar mass of O₂ = 32 g/mol
  • Mole of of O₂ (n) = 885 / 32 = 27.65625 moles
  • Temperature (T) = 21 °C = 21 + 273 = 294 K
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Pressure (P) =?

The pressure of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both side by V

P = nRT / V

P = (27.65625 × 0.0821 × 294) / 438

P = 1.524 atm

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

Learn more about ideal gas equation:

brainly.com/question/4147359

6 0
2 years ago
(QUICK PLEASE!)
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Answer:

It pushes back with equal force.

Explanation:

This is pretty much newton's first law.

4 0
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