Molar mass Na₂SO₄. 10H₂O = 322.19 g/mol
Molar mass H₂O = 18.0
% Element = molar mass / total mass x 100
% Element = 18 / 322,19 x 100
% Element = 5.59 %
Answer A
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Answer: GeH4 (Germanium(IV) Hydride)
Explanation:
A Binary molecular compound Hydrogen and a Group 4A element which is more more acidic than SiH4 in aqueous solution is GeH4.
The pKa of GeH4;
= 25
Whilst that of SiH4
= 35
The lesser the pKa the higher the Ka which means more acidic.
Answer: 0.5 mole Mg
Explanation: solution:
12 g Mg x 1 mole Mg / 24 g Mg
= 0.5 mole Mg
Answer:
ΔH°_rxn = -195.9 kJ·mol⁻¹
Explanation:
4NH₃(g) + 3O₂(g) ⟶ 2N₂(g) +6H₂O(g)
ΔH°_f/(kJ·mol⁻¹): -45.9 0 0 -241.8
The formula relating ΔH°_rxn and enthalpies of formation (ΔH°_f) is
ΔH°_rxn = ΣΔH°_f(products) – ΣΔH°_f(reactants)
ΣΔH°_f(products) = -6(241.8) = -1450.8 kJ
ΣΔH°_f(reactants) = -4(45.9) = -183.6 kJ
ΔH°_rxn = (-1450.8 + 183.6) kJ = -1267.2 kJ