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3 years ago

What is the effect of adding a pre-made mix to alcohol?

Chemistry

1 answer:

Maurinko [17]3 years ago

5 0

Is not adequate to prevent dehydration effects in the cell

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NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Zanzabum

True

Explanation:

It is correct to say that the biosphere includes all of the fish that are in the ocean. Even though the ocean is part of the hydrosphere.

The biosphere includes all life form on earth wherever they may dwell from deep abyss to the high atmosphere.

The different spheres on earth are interacting with one another and they depend on each other.

Just like the earth systems, the spheres of the earth relates with each other. Even the ocean is contained in the geosphere.

learn more:

Biodiversity brainly.com/question/10723602

#learnwithBrainly

3 0

3 years ago

Will a precipitate of magnesium fluoride form when 300. mL of 1.1 × 10 –3 M MgCl 2 are added to 500. mL of 1.2 × 10 –3 M NaF? [K

Tju [1.3M]

Answer:

No precipitate is formed.

Explanation:

Hello,

In this case, given the dissociation reaction of magnesium fluoride:

$MgF_2(s)\rightleftharpoons Mg^{2+}+2F^-$

And the undergoing chemical reaction:

$MgCl_2+2NaF\rightarrow MgF_2+2NaCl$

We need to compute the yielded moles of magnesium fluoride, but first we need to identify the limiting reactant for which we compute the available moles of magnesium chloride:

$n_{MgCl_2}=0.3L*1.1x10^{-3}mol/L=3.3x10^{-4}molMgCl_2$

Next, the moles of magnesium chloride consumed by the sodium fluoride:

$n_{MgCl_2}^{consumed}=0.5L*1.2x10^{-3}molNaF/L*\frac{1molCaCl_2}{2molNaF} =3x10^{-4}molMgCl_2$

Thus, less moles are consumed by the NaF, for which the moles of formed magnesium fluoride are:

$n_{MgF_2}=3x10^{-4}molMgCl_2*\frac{1molMgF_2}{1molMgCl_2}=3x10^{-4}molMgF_2$

Next, since the magnesium fluoride to magnesium and fluoride ions is in a 1:1 and 1:2 molar ratio, the concentrations of such ions are:

$[Mg^{2+}]=\frac{3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =3.75x10^{-4}M$

$[F^-]=\frac{2*3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =7.5x10^{-4}M$

Thereby, the reaction quotient is:

$Q=(3.75x10^{-4})(7.5x10^{-4})^2=2.11x10^{-10}$

In such a way, since Q<Ksp we say that the ions tend to be formed, so no precipitate is formed.

Regards.

6 0

2 years ago

What is the valency of Aluminium and nitrate in Al(NO3)3 ?

Kitty [74]

Answer:xl/ck xLKsx

Explanation:sl/cs c/ls

3 0

2 years ago

How many significant figures are in 1.00 L

likoan [24]

Answer:

3 significant numbers

6 0

3 years ago

Which of the following changes will always be true for a spontaneous reaction? (3 points)

Alika [10]

Answer is: - delta G.
The change in Gibbs free energy (ΔG), at constant temperature and pressure, is: ΔG=ΔH−TΔS.
ΔH is the change in enthalpy.
ΔS is change in entropy.
T is temperature of the system.
When ΔG is negative, a reaction (occurs without the addition of external energy) will be spontaneous (exergonic).

3 0

2 years ago