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NikAS [45]
3 years ago
7

Which of the following pictures correctly show the structure of the H+ ion? Click on the picture to see each choice.

Chemistry
2 answers:
lutik1710 [3]3 years ago
7 0

Answer: It's only one proton in the middle of the red circle there's nothing outside it.

Explanation: I'm not sure sorry :|

hope this helps

mr Goodwill [35]3 years ago
6 0

Answer: The answer is the one with the letter P in the red circle.

Explanation:

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What would the total mass of a 4.9 mole sample of Barium (Ba) be if its Molar Mass is 137g?
Aleksandr-060686 [28]

Answer:

m = 671 grams

Explanation:

Given that,

No of moles, n = 4.9

Molar mass of Barium, M = 137 g

Mass divided by molar mass is equal to no of moles. It can be given by the formula as follows :

n=\dfrac{m}{M}\\\\m=n\times M\\\\m=4.9\times 137\\\\m=671.3\ g

or

m = 671 grams

So, the total mass of the sample of Barium is 671 grams.

8 0
3 years ago
How many values of these of these trials can be considered accurate?
Gnoma [55]

Answer:

go to google

Explanation:it all ways work

6 0
3 years ago
For some hypothetical metal, the equilibrium number of vacancies at 600°C is 1 × 1025 m-3. If the density and atomic weight of t
makvit [3.9K]

Answer:

\frac{N_{v}}{N}=1.92*10^{-4}

Explanation:

First of all we need to find the amount of atoms per volume (m³). We can do this using the density and the molar mass.

7.40 \frac{g}{cm^{3}}*\frac{1mol}{85.5 g}*\frac{6.023*10^{23}atoms}{1mol}*\frac{1000000 cm^{3}}{1m^{3}}=5.21*10^{28}\frac{atoms}{m^{3}}

Now, the fraction of vacancies is equal to the N(v)/N ratio.

  • N(v) is the number of vacancies 1*10^{25}m^{-3}
  • N is the number of atoms per volume calculated above.

Therefore:  

The fraction of vacancies at 600 °C will be:

\frac{N_{v}}{N}=\frac{1*10^{25}}{5.21*10^{28}}  

\frac{N_{v}}{N}=1.92*10^{-4}

I hope it helps you!

 

7 0
3 years ago
What would be the right answer?
KengaRu [80]

Answer:

5 is the answer since they are asking for pair. And 3 pairs in the triple bond

4 0
3 years ago
Read 2 more answers
what is the number of kilograms of solvent in a 0.70 molal solution containing 5.0 grams of solute? (molar mass of solute
pshichka [43]

The number of kilograms of solvent is 0.238 kg.

Moles of solute = given mass/ molar mass

                        = 5.0 g/ 30g/mol

                       = 0.167 mol

Molality = Moles of solute/ weight of solvent (in kg)

0.70 m = 0.167 mol/ weight of solvent (in kg)

Weight of solvent (in kg) = 0.167/0.70

Weight of solvent (in kg) = 0.238 kg

Hence, the number of kilograms of solvent is 0.238 kg.

Molality is a degree of the number of moles of solute in a solution corresponding to 1 kg or a thousand g of solvent. This contrasts with the definition of molarity that is primarily based on a distinctive quantity of answer. A commonly used unit for molality in chemistry is mol/kg.

Find out how molarity and molality fluctuate! The molality of a solution is identical to the moles of solute divided by way of the mass of solvent in kilograms, whilst the molarity of an answer is identical to the moles of solute divided by the volume of solution in liters.

Learn more about Molality here:-

brainly.com/question/9149034

#SPJ4

7 0
2 years ago
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