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Serhud [2]
4 years ago
5

Can someone answer the question​

Physics
1 answer:
Alja [10]4 years ago
6 0

Answer:

its A

Explanation:

The transfer of heat from a hot object to a cold object continues until the two bodies are at the same temperature

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Which of the following statements are true for electric field lines? Check all that apply. Check all that apply. Electric field
Scilla [17]

Answer:

Electric field lines point away from positive charges and toward negative charges. <u>True</u>

Electric field lines are continuous; they do not have a beginning or an ending.<u> False</u>

Electric field lines can never intersect. <u>True</u>

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. <u>False</u>

At every point in space, the electric field vector at that point is tangent to the electric field line through that point.<u> True</u>

Explanation:

Electric field lines point away from positive charges and toward negative charges. Always the field lines go to negative charges and leave from positive charges.

Electric field lines are continuous; they do not have a beginning or an ending.<u> False  </u>

Because the field lines starts at positive charges and ends in negative charges.

Electric field lines can never intersect. <u>True</u>

It can not intercept the field lines because in that point the the field would have two directions. Besides, in that point the real value of the field should be found adding both field lines.

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. <u>False</u>

This fact is opposite to that so the regions of space where the magnitude the electric field is weak the lines are father apart and where the field is strong  the lines are close together.

At every point in space, the electric field vector at that point is tangent to the electric field line through that point.<u> True</u>

This statement correspond to the definition of the field line.

5 0
3 years ago
Monochromatic light of wavelength λ=620nm from a distant source passes through a slit 0.450 mm wide. The diffraction pattern is
Elan Coil [88]

Answer:

The intensity of light from the 1mm from the central maximu is  I = 0.822I_o

Explanation:

From the question we are told that

                         The wavelength is \lambda = 620 nm = 620 *10^{-9}m

                         The width of the slit is w = 0.450mm = \frac{0.45}{1000} = 0.45*10^{-3} m  

                          The distance from the screen is  D = 3.00m

                           The intensity at the central maximum is I_o

                          The distance from the central maximum is d_1 = 1.00mm = \frac{1}{1000} = 1.0*10^{-3}m

        Let z be the the distance of a point with intensity I from central maximum

Then we can represent this intensity as

                     I = I_o [\frac{sin [\frac{\pi * w * sin (\theta )}{\lambda} ]}{\frac{\pi * w * sin (\theta )}{\lambda } } ]^2

    Now the relationship between D and z can be represented using the SOHCAHTOA rule i.e

            sin \theta = \frac{z}{D}

           

if the angle between the the light at z and the central maximum is small

Then  sin \theta =  \theta

   Which implies that

              \theta = \frac{z}{D}

substituting this into the equation for the intensity

             I = I_o [\frac{sin [\frac{\pi w}{\lambda} \cdot \frac{z}{D}  ]}{\frac{\pi w z}{\lambda D\frac{x}{y} } } ]

given that z =1mm = 1*10^{-3}m

   We have that

              I = I_o [\frac{sin[\frac{3.142 * 0.45*10^{-3}}{(620 *10^{-9})} \cdot \frac{1*10^{-3}}{3} ]}{\frac{3.142 * 0.45*10^{-3}*1*10^{-3} }{620*10^{-9} *3} } ]^2

                 =I_o [\frac{sin(0.760)}{0.760}] ^2

                 I = 0.822I_o

               

 

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Latortugade bisagra de Cuatro Ciénegas habita exclusivamente en las pozas de agua dulce del valle de Cuatro Ciénegas, en el cent
Nadusha1986 [10]

Answer:

son 20184 esa es la respuesta

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3 years ago
What is the momentum of a 200 kg car traveling 30 m/s to the right?
hichkok12 [17]
Momentum=mass × velocity
momentum= 200×30
=6000kgm/s
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4 years ago
Convection occurs when thermal energy is transferred by the movement of
madam [21]

Answer:

Convection is the transfer of thermal energy from one place to another by the movement of gas or liquid particles. How does this happen? As a gas or liquid is heated, the substance expands. This is because the particles in liquids and gases gain kinetic energy when they are heated and start to move faster.

6 0
3 years ago
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