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oksano4ka [1.4K]
3 years ago
11

What evidence is there that electrons move around in definite pathways around the

Chemistry
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

Absorption and emission spectra

Explanation:

This is occurs when an atom either absorbs or emits energy when bombarded by a source.

Neils Bohr predicted that electrons moves round in the atom in distinct orbitals according to their energy. An electron in its ground state can become excited if it gains sufficient energy which surpasses that of its ground state configuration. An atom can also move from higher energy levels to lower ones. During the descent, energy is given off in form of emission spectra.

Absorption occurs when electrons in an atom absorbs energy from incoming radiation and they re-radiate it in all directions. This is given off as a spectra and can be observed for such electron.

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Balance the following equation. Then determine the ratio for the products KCl and O2 generated during the decomposition of potas
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Based on the kinetic theory, which statement is true?
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why are plasmas of great interest to scientists or manufacturers. descride 2 current uses of plasmas and describe 1 way scientis
Helga [31]

<u>Answer:</u>

<u>Plasmas of great interest to scientists or manufacturers as</u>

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<u>Current uses of plasmas:</u>

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6 0
3 years ago
Propane is often used to heat homes. The combustion of propane follows the following reaction: C3H8(g) + 5O2(g)  3CO2 (g) + 4H
swat32

Answer:

To release 7563 kJ of heat, we need to burn 163.17 grams of propane

Explanation:

<u>Step 1</u>: Data given

C3H8 + 5O2 -----------> 3CO2 + 4H2O      ΔH° = –2044 kJ

This means every mole C3H8

Every mole of C3H8 produces 2044 kJ of heat when it burns (ΔH° is negative because it's an exothermic reaction)

<u>Step 2: </u>Calculate the number of moles to produce 7563 kJ of heat

1 mol = 2044 kJ

x mol = 7563 kJ

x = 7563/2044 =  3.70 moles

To produce 7563 kJ of heat we have to burn 3.70 moles of C3H8

<u>Step 3: </u>Calculate mass of propane

Mass propane = moles * Molar mass

Mass propane = 3.70 moles * 44.1 g/mol

Mass propane = 163.17 grams

To release 7563 kJ of heat, we need to burn 163.17 grams of propane

7 0
3 years ago
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