Answer: the percentage of acetic acid will be low.
Explanation: The major aim during titration of acids and bases is to determine the endpoint , that is exact point where the acid in the beaker changes colour, (in this case, pink )with an additional drop from the burette containing the base, since it is usually difficult to mark the equivalence point that tells us when all the substrate in the beaker has been neutralized completely with the buretted substance.
Overshooting the end point is an error which can occur when the person involved in the the titration accidently goes beyond this endpoint by adding too much of the substance(base) from the burette into the beaker missing the exact endpoint.
This implies that the person has added too much of the burreted liquid, ie the base than required , making the acid in the beaker to continue to react resulting to a lower concentration of the acid (acetic acid) with excess base.(NaOH)
Petroleum is used as a fuel to power vehicles and machines.
Petroleum products include fuel oils for heating and electricity generation.
It is a feedstocks for making the chemicals and plastics.
We use petroleum to produce electricity.
Answer:
The new volume of the gas is 4.74L
Explanation:
Data;
T1 = 14°C = (14 + 273.15)K = 287.15K
V1 = 4.5L
T2 = 29°C = (29 + 273.15)K = 302.15
V2 = ?
From Charles law,
The volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant.
Mathematically,
V = kT
k = V1 / T1 = V2 / T2 = V3 / T3 = .............= Vn / Tn.
V1 / T1 = V2 / T2
Solving for V2
V2 = (V1 * T2) / T1
V2 = (4.5 * 302.15) / 287.15
V2 = 4.735L
V2 = 4.74L
The new volume of the gas is 4.74L
The new volume is 1.9 ml
<u><em> calculation</em></u>
The new volume is calculated using the combined gas equation
that is P1V1/T1 = P2V2/T2 where
P1= 1.0 atm
V1= 21 ml
T1 = 10.0 c into kelvin = 10 + 273 = 283 k
P2 = 15 atm
V2=? Ml
T2 = 120 c into kelvin = 120 +273 = 393 K
make V2 the subject of the formula by multiplying both side by T2/P2
V2=T2P1v1 / P2T1
V2=[(393 k x 1.0 atm x 21 ml) / (15 atm x 283 K)] = 1.9 Ml
