Answer:
79.0 g
Explanation:
1. Gather the information in one place.
MM: 148.89 253.81
2NaI + Cl2 → I2 + 2NaCl
m/g: 67.3
2. Moles of I2
n = 67.3 g × (1 mol/253.81 g) = 0.2652 mol I2
2. Moles of NaI needed
From the balanced equation, the molar ratio is 2 mol NaI: 1 mol I2
n = 0.028 76 mol I2× (2 mol NaI/1 mol I2) = 0.5303 mol NaI
3. Mass of NaI
m = 0.5303 mol × (148.89 g/1 mol) = 79.0 g NaI
It takes 79.0 g of NaI to produce 67.3 g of I2.
The nuclear equation :
₈₂²¹⁴Pb ⇒ ₈₃²¹⁴Bi + ₋₁⁰e
<h3>Further explanation
</h3>
Given
₈₂²¹⁴Pb
beta β ₋₁e⁰ particles
Required
Nuclear equation
Solution
Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
-
alpha α particles ₂He⁴
- beta β ₋₁e⁰ particles
- gamma particles ₀γ⁰
- positron particles ₁e⁰
- neutron ₀n¹
The principle used is the sum of the atomic number and mass number before and after the decay reaction is the same
The reaction
₈₂²¹⁴Pb ⇒ X + ₋₁⁰e
The element X has
-the atomic number = 82 + 1 = 83
-the mass number = 214
In the periodic system, the element with atomic number 83=Bismuth
CO2 is a compound, hope this is okay
Answer:
The salt, LiNO₃ is a neutral, NR salt as it's a salt formed from the reaction of a strong acid and a strong base.In neutralisation reactions, acids and bases react to form salt and water.However, the salt formed may be acidic, basic or neutral. This is dependent on the type of acid and base which form the salt.A strong acid and a strong base react to yield a neutral salt like, LiNO₃.The equilibrium equation when LiNO₃ is dissolved in aqeous solution is;LiNO₃ + H2O ==>. LiOH + HNO₃
Explanation:
<span> We are given with the rate constant of a first-order decomposition of n2o which is equal to 3.40 s-1. Half life of the radioactive material can be determined through the formula: t= ln2 /k where t is the half life of the material. t then upon substitution is equal to 0.2048 s. </span>
