Conception is the correct answer
Answer:
Explanation:
Let mass of cylinder be M
Moment of inertia of cylinder
= 1/2 M R² r is radius of cylinder
If radius of equivalent hoop be k
Mk² = 1/2 x MR²
k = R / √2
1.2 / 1.414
Radius of gyration = 0.848 m
b )
moment of inertia of spherical shell
= 2 / 3 M R²
Moment of inertia of equivalent hoop
Mk²
So
Mk² = 2 / 3 M R²
k = √2/3 x R
= .816 X 1.2
Radius of gyration = .98 m
c )
Moment of inertia of solid sphere
= 2/5 M R²
Moment of inertia of equivalent hoop
= Mk²
Mk² = 2/5 M R²
k √ 2/5 R
Radius of gyration = .63 R
B and C because an earthquake does not directly affect gravity, and precipitation doesn’t fall, it is water surfacing
The force of gravity = GMm / r^2, where G is gravitational constant, M is mass of one object, m is mass of another object, r is distance between them.
To make gravity smaller, decrease mass or increase distance.
To make gravity bigger, increase mass or decrease distance.
