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3 years ago

Which statement best describes wavelength

Physics

2 answers:

mezya [45]3 years ago

8 0

The distance between one crest and the second

wlad13 [49]3 years ago

4 0

The distance between ON crest and the second one.

You might be interested in

What inertia is present in a stretched rubber?

iVinArrow [24]

Answer:

You input potential energy into the rubber band system when you stretched the rubber band back. Because it is an elastic system, this is kind of potential energy is specifically called elastic potential energy.

7 0

4 years ago

) The square plates of a 5000-pF parallel-plate capacitor measure 50 mm by 50 mm and are separated by a dielectric that is 0.23

notsponge [240]

Answer:

4 x 10⁻⁴ J

Explanation:

C = 5000 pF, V = 400 V

Energy = CV²/2 = 5000 x 10⁻¹² x 400²/2 = 4 x 10⁻⁴ J

6 0

2 years ago

A block is attached to a horizontal spring and oscillates back and forth on a frictionless horizontal surface at a frequency of

Nastasia [14]

Answer:

Amplitude = 0.058m

Frequency = 6.25Hz

Explanation:

Given

Amplitude (A) = 8.26 x 10-2 m

Frequency (f) = 4.42Hz

Conversation of energy before split

½mv² = ½KA²

Make A the subject of formula

A = $v\sqrt{\frac{m}{k} }$

Conversation of energy after split

½(m/2)V'² = ½(m/2)V² = ½KA'²

½(m/2)V² = ½KA'²

Make A the subject of formula

First divide both sides by ½

(m/2)V² = KA'²

Divide both sides by K

$\frac{m}{2K}$ V² = A'²

$v\sqrt{\frac{m}{2k} }$ = A'

Substitute $v\sqrt{\frac{m}{k} }$ for A in the above equation

A' = A/√2

A' = 8.26 x 10^-2/√2

A' = 0.05840702012600882

Amplitude after split = 0.058 (Approximated)

Frequency (f') = f√2

f' = 4.42√2

f' = 6.25082394568908011

Frequency after split = 6.25Hz (approximated)

8 0

3 years ago

Pangaea was not the first, nor will it be the last, super continent. In the process of continental drift, sometimes chunks of co

Karolina [17]

Answer:

Explanation:

there could be earthquakes or the tectonic plates under can make it fall apart, natural disasters

hope this helps!!

6 0

3 years ago

The coordinates of a particle in the metric xy-plane are differentiable functions of time t with StartFraction dx Over dt EndFr

Brut [27]

Answer:

$\dfrac{dD}{dt}=-7.076\ m/s$

Explanation:

It is given that,

The coordinates of a particle in the metric xy-plane are differentiable functions of time t are given by :

$\dfrac{dx}{dt}=-6\ m/s$

$\dfrac{dy}{dt}=-4\ m/s$

Let D is the distance from the origin. It is given by :

$D^2=x^2+y^2$

Differentiate above equation wrt t as:

$2D\dfrac{dD}{dt}=2x\dfrac{dx}{dt}+2y\dfrac{dy}{dt}$

$D\dfrac{dD}{dt}=x\dfrac{dx}{dt}+y\dfrac{dy}{dt}$ .............(1)

The points are given as, (12,5). Calculating D from these points as :

$D=\sqrt{12^2+5^2} =13\ m$

Put all values in equation (1) as :

$13\times \dfrac{dD}{dt}=12\times (-6)+5\times (-4)$

$\dfrac{dD}{dt}=-7.076\ m/s$

So, the particle is moving away from the origin at the rate of 7.076 m/s. Hence, this is the required solution.

4 0

3 years ago