Answer:
(i) Electric field outside the shell:
For point r>R; draw a spherical gaussian surface of radius r.
Using gauss law, ∮E.ds=q0qend
Since E is perpendicular to gaussian surface, angle betwee E is 0.
Also E being constant, can be taken out of integral.
So, E(4πr2)=q0q
So, E=4πε01r2q
Velocity units =m/s
Acceleration is the rate of change of velocity
a =timechange in velocity
Therefore SI units of acceleration is ms−1/s=s2m
Answer:

Explanation:
The attached image shows the system expressed in the question.
We can define an expression for the system.
The equivalent equation for the system would be

so, the input signal could be expressed in dB terms
(1)
so the output signal could be expressed as.

The gain should be expressed in dB terms and power in dBm terms so

using the (1) equation to find it in terms of Watts

The first one, directly proportional to the length that the spring is stretched.
Explanation:
radio waves, which include visible light waves.