It is +5. There -8 charge due to four oxygen atoms and +3 due to one sodium atom and 2 hydrogen atom which makes it necessary for phosphorus to have +5 charge on it to make the compound electrically neutral. The charge on phosphorus corresponds to its oxidation number.
1 mol of any substance is made of 6.022 x 10²³ units, these units could be atoms making up elements or molecules making up a compound.
In this case. 1 mol of Li is made of 6.022 x 10²³ atoms of Li
The molar mass of Li is 6.94 g/mol
Therefore mass of 1 mol of Li is 6.94 g
In 6.94 g of Li there are - 6.022 x 10²³ atoms
Then in 766.3 g of Li there are - 6.022 x 10²³ atoms / 6.94 g x 766.3 g = 665 x 10²³
There are 6.65 x 10^25 atoms of Li
Answer:
Molality = 1.428m
Explanation:
Molality, m, is an unit of concentration defined as the ratio between moles of solute and kg of solvent:
Molality: Moles solute / kg solvent.
In the problem, water is the solvent (Is the compound in the higher quantity) whereas NaNO₃ is the solute.
Moles of solute: 0.3355moles NaNO₃.
Kg solvent:
Thus, molality of the solution is:
Molality = 0.3355 moles NaNO₃ / 0.2350kg
<h3>Molality = 1.428m</h3>
it would be heating of 32g of s and 56g of Fe to produce 88g of FeS and unused reactants
Answer:
Carbonates (CO3-2), phosphates (PO4-3) and sulfides (S-2) are insoluble.
The exceptions are the alkali metals and the ammonium ion.
