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sesenic [268]
3 years ago
13

One mole of an ideal gas is expanded from a volume of 1.00 liter to a volume of 8.00 liters against a constant external pressure

of 1.00 atm. How much work (in joules) is performed on the surroundings? Ignore significant figures for this problem. (T = 300 K; 1 L·atm = 101.3 J)
Chemistry
1 answer:
Leya [2.2K]3 years ago
4 0

Answer : The work done on the surroundings is, 709.1 Joules.

Explanation :

The formula used for isothermally irreversible expansion is :

w=-p_{ext}dV\\\\w=-p_{ext}(V_2-V_1)

where,

w = work done

p_{ext} = external pressure = 1.00 atm

V_1 = initial volume of gas = 1.00 L

V_2 = final volume of gas = 8.00 L

Now put all the given values in the above formula, we get :

w=-p_{ext}(V_2-V_1)

w=-(1.00atm)\times (8.00-1.00)L

w=-7L.atm=-7\times 101.3J=-709.1J

The work done by the system on the surroundings are, 709.1 Joules. In this, the negative sign indicates the work is done by the system on the surroundings.

Therefore, the work done on the surroundings is, 709.1 Joules.

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3 years ago
Draw the products of the complete hydrolysis of an acetal. Draw all products of the reaction.
jolli1 [7]

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8 0
3 years ago
What mass of copper is deposited when a current of 10.0a is passed through a solution of copper(ii) nitrate for 30.6 seconds?
asambeis [7]
Data Given:

Time = t = 30.6 s

Current = I = 10 A

Faradays Constant = F = 96500

Chemical equivalent = e = 63.54/2 = 31.77 g

Amount Deposited = W = ?

Solution:
             According to Faraday's Law,

                                          W  =  I t e / F

Putting Values,
 
                            W  =  (10 A × 30.6 s × 31.77 g) ÷ 96500

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Result:
           0.100 g of Cu
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