Answer:
nitrogen oxides and sulphur oxides
Explanation:
Factors responsible for antropogenic pollution are:
- burning of fossil fuels
- deforestation
- mining
- sewage
- industrial effluent
- pesticides, fertilizers, etc.
The primary air pollutants released from burning of fossil fuels are oxides of nitrogen, sulfur oxides and carbon monoxide.
Out of which the main pollutants that are responsible for acidic precipitation are oxides of nitrogen and sulfur oxides.
Sulfur oxides and Oxides of nitrogen reacts with moisture present in the air to form sulfuric acid and nitric acid respectively.
These acids get mixed with rain and cause acidic precipitation.
Therefore, the correct option is oxides of nitrogen and sulfur oxides.
Answer:
1. increase the temperature
2. increase the concentration of reactants
3. increase the surface area of the reactants
4. use a catalyst
5. remove the product as it's formed
Explanation:
for a chemical reaction to take place, the bonds between atoms in the reactants are broken, the atoms rearrange and new bonds between the atoms are formed to make the products.
Answer:
Cytokinesis is the process by which one cell physically separates into two daughter cells at the end of each division cycle. In metazoan cells, the division plane, termed the cell equator, is determined by microtubules of the anaphase spindle.
Explanation:
Answer:
c. 1.4 x 10²³ oxygen atoms
Explanation:
The number of oxygen atoms in one molecule of CH₃COOH is 2.
Avogadro's constant relates the number of molecules in one mole:
6.022 × 10²³ mol⁻¹
Thus, the number of oxygen atoms in one molecule of acetic acid can be converted to the number of oxygen atoms in one mole of acetic acid:
(2 oxygen atoms / molecule)(6.022 × 10²³ molecule / mol) = 1.204 x 10²⁴ atoms per mole
Finally, the number of oxygen atoms in 0.12 moles of acetic acid are calculated:
(1.204 x 10²⁴ atoms / mol)(0.12 mol) = 1.4 x 10²³ atoms/mol
Answer:
the volume of CHCI3 = 7.87 ml
the volume of CHBr3 = 12.13 ml
Explanation:
From the given information:
We all know that 1 g/cm^3 = 1 g/ml
The density of boron = 2.34 g/ml
The Volume of the liquid mixture = 20 ml
Recall that:
Density = mass/volume
Mass = Density × Volume
Mass = 2.34 g/ml × 20 ml
Mass = 46.8 g
Suppose the volume of CHCI3 be Y and the Volume of CHBr3 be 20 - Y
Then :
Y (1.492) + 20-Y(2.890) = 46.8
1.492Y + 57.8 - 2.890Y = 46.8
- 1.398 Y = -11
Y = -11/ - 1.398
Y = 7.87 ml
Therefore, the volume of CHCI3 7.87 ml
the volume of CHBr3 = 20 - Y
= 20 - 7.87
= 12.13 ml