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Temka [501]
3 years ago
5

1.Which of the following compounds give acidic solution with water:

Chemistry
1 answer:
m_a_m_a [10]3 years ago
7 0

Answer:

3

Explanation:

metallic oxides are basic in nature.

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Question 1 of 6
Juli2301 [7.4K]

Answer:

Option A. 2, 3, 2

Explanation:

We'll begin by balancing the equation. This can be achieved by doing the following:

Fe + Cl2 —> FeCl3

There are 2 atoms of Cl on the left side and 3 atoms on the right side. It can be balance by putting 3 in front of Cl2 and 2 in front of FeCl3 as shown below:

Fe + 3Cl2 —> 2FeCl3

There are 2 atoms of Fe on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Fe as shown below:

2Fe + 3Cl2 —> 2FeCl3

Now the equation is balanced.

The coefficients are : 2, 3, 2

8 0
3 years ago
Discuss whether two products are required for a chemical reaction. (NEED HELP ASAP)
Alex787 [66]

Answer:

Yes.

Explanation:

"These starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products."

There is a beginning product, and a reactant is needed in order for something to happen.

For example, according to Newton, something cannot happen until an exterior force comes and stops/pushes it.

Sorry if this is incorrect, I am just 4th grade :(

6 0
3 years ago
how much heat is released when 70.9g of water at 66C cools to 25C? The specific heat of water is 1 cal/gC
Serga [27]

Answer:

-12162.47 joules (or -12000 joules when accounting for significant figures)

Explanation (btw I used 1 cal as 4.184 joules because SI units are better):

q = m c delta T

q = (70.9) (4.184) (25 - 66)  

q = (70.9) (4.184) (-41)

q = -12162.47 joules

7 0
3 years ago
If 120.3 mL of water is shaken with oxygen gas at 2.1 atm, it will dissolve 0.0043 g O2. Estimate the Henry's law constant for t
nikklg [1K]

<u>Answer:</u> The Henry's law constant for oxygen gas in water is 1.702\times 10^{-5}g/mL.atm

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{O_2}=K_H\times p_{O_2}

where,

K_H = Henry's constant = ?

C_{O_2} = solubility of oxygen gas = 0.0043g/120.3mL

p_{O_2 = partial pressure of oxygen gas = 2.1 atm

Putting values in above equation, we get:

0.0043g/120.3mL=K_H\times 2.1atm\\\\K_H=\frac{0.0043g}{120.3mL\times 2.1atm}=1.702\times 10^{-5}g/mL.atm

Hence, the Henry's law constant for oxygen gas in water is 1.702\times 10^{-5}g/mL.atm

7 0
3 years ago
Which of the following systems has potential energy only?
DIA [1.3K]

Answer:

a bird sitting on a branch

6 0
3 years ago
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