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Nastasia [14]
3 years ago
7

What is the temperature of a star (in Kelvin) if its peak wavelength is 150 nm (that is, 150 x 10^-9 m)?

Physics
1 answer:
liq [111]3 years ago
7 0

Answer:

19320 K

Explanation:

The temperature of a star is related to its peak wavelength by Wien's displacement law:

T=\frac{b}{\lambda}

where

T is the absolute temperature at the star's surface

b=2.898 \cdot 10^{-3}m\cdot K is Wien's displacement constant

\lambda is the peak wavelength

Here we have

\lambda=150 nm = 150\cdot 10^{-9}nm

Substituting into the equation, we find

T=\frac{2.898\cdot 10^{-3}}{150\cdot 10^{-9}}=19320 K

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Phương trình trạng thái tổng quát của khí lí tưởng diễn tả là​
tatyana61 [14]

Expla

pV/T=const goodluke

6 0
3 years ago
When the distance between two charges is halved, the electrical force between them?
Llana [10]
If the distance between two charges is halved, the electrical force between them increases by a factor 4.

In fact, the magnitude of the electric force between two charges is given by:
F= k \frac{q_1 q_2}{r^2}
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges

We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:
r'= \frac{r}{2}
the magnitude of the force changes as follows:
F'=k \frac{q_1 q_2}{r'^2}=k \frac{q_1 q_2}{( \frac{r}{2})^2 }=k \frac{q_1 q_2}{ \frac{r^2}{4} } =4k  \frac{q_1 q_2}{r^2}=4 F
so, the force increases by a factor 4.
3 0
3 years ago
Through what vertical height is a 50 N object moved if 250 J of work is done lifting it against the gravitational field of Earth
zimovet [89]

5m

Explanation:

Given parameters:

Weight of object = 50N

Work done in lifting object = 250J

Unknown:

Vertical height = ?

Solution:

The work done on an object is the force applied to lift a body in a specific direction.

   Work done = force x distance

  Weight is a force in the presence of gravity;

  Work done = weight x height of lifting

Height of lifting = \frac{work done }{weight}

 Height of lifting = \frac{250}{50} = 5m

The vertical height through which the object was lifted is 5m

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

6 0
3 years ago
While strolling downtown on a Saturday afternoon, you stumble across an old car show. As you are walking along an alley toward a
snow_tiger [21]

Answer:

1.44 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v=u+at\\\Rightarrow v=0+a\times 5\\\Rightarrow v=5a

This velocity will be the initial velocity of the car when it passes through the first building

s=ut+\frac{1}{2}at^2\\\Rightarrow 3=5a\times 0.4+\frac{1}{2}\times a\times 0.4^2\\\Rightarrow a=1.44\ m/s^2

The acceleration of the car is 1.44 m/s²

7 0
3 years ago
The ability to clearly see objects at a distance but not close up is properly called ________. The ability to clearly see object
melamori03 [73]

Answer:

Hyperopia

Explanation:

     In hyperopia ,people face difficulties  to see close up object , but can see object easily which are at a distance.

The main reason of hyperopia is our eyeball.When our eyeball become too  short , then light focus behind the retina. Sowe will face problem to see near object but we can see distance object easily. Hyperopia is the opposite of nearsightedness. Hyperopia can be corrected by using contact lenses.

5 0
3 years ago
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