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DanielleElmas [232]
3 years ago
15

An organism is composed of several organ systems. Often, the different organ systems work together towards a common purpose. For

example, going for a run requires the use of several different organ systems. List two systems below and describe how they are used while running. *
Physics
2 answers:
asambeis [7]3 years ago
7 0

Answer:

A number of body systems are used when we are running. These systems include the nervous system, skeletal system, muscular system, respiratory system and the circulatory system. When we decide to run, a signal is sent from our brain to our muscles through the nervous system. Once the signal is received, our muscles starts to contract and we start running using our legs. The process of running uses a lot of energy and this energy is provided to us by cellular respiration. We use the respiratory system to bring oxygen into the body, where it interacts with food and generates energy. The carbon dioxide produced is removed by the respiratory system. The gases are transported throughout the body by our circulatory system. Thus, a number of body systems work in conjunction to enable a simple activity like running.

Hope this helps.

Gemiola [76]3 years ago
4 0

Answer:

Skeletal system, muscular system

Explanation:

Skeletal system:

bones

Muscular system:

muscles

Together, they work together and create the musculoskeletal system.

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A third point charge q3 is now positioned halfway between q1 and q2. The net force on q2 now has a magnitude of F2,net = 14.413
natima [27]

Answer:

The value of  charge q₃ is 40.46 μC.

Explanation:

Given that.

Magnitude of net force F=14.413\ N

Suppose a point charge q₁ = -3 μC is located at the origin of a co-ordinate system. Another point charge q₂ = 7.7 μC is located along the x-axis at a distance x₂ = 8.2 cm from q₁. Charge q₂ is displaced a distance y₂ = 3.1 cm in the positive y-direction.

We need to calculate the distance

Using Pythagorean theorem

r=\sqrt{x_{2}^2+y_{2}^2}

Put the value into the formula

r=\sqrt{(8.2\times10^{-2})^2+(3.1\times10^{-2})^2}

r=0.0876\ m

We need to calculate the magnitude of the charge q₃

Using formula of net force

F_{12}=kq_{2}(\dfrac{q_{3}}{r_{3}^2}+\dfrac{q_{1}}{r_{1}^2})

Put the value into the formula

14.413=9\times10^{9}\times7.7\times10^{-6}(\dfrac{q_{3}}{(0.0438)^2}+\dfrac{-3\times10^{-6}}{(0.0876)^2})

(\dfrac{q_{3}}{(4.38\times10^{-2})^2}+\dfrac{-3\times10^{-6}}{(0.0876)^2})=\dfrac{14.413}{9\times10^{9}\times7.7\times10^{-6}}

\dfrac{q_{3}}{(0.0438)^2}=207\times10^{-4}+3.909\times10^{-4}

q_{3}=0.0210909\times(0.0438)^2

q_{3}=40.46\times10^{-6}\ C

q_{3}=40.46\ \mu C

Hence, The value of  charge q₃ is 40.46 μC.

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Given

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Explanation

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Conclusion

The equivalent resistance is 21 ohm

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Sphinxa [80]

Answer:

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Explanation:

<em>I hope this helps.</em>

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