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DanielleElmas [232]
3 years ago
15

An organism is composed of several organ systems. Often, the different organ systems work together towards a common purpose. For

example, going for a run requires the use of several different organ systems. List two systems below and describe how they are used while running. *
Physics
2 answers:
asambeis [7]3 years ago
7 0

Answer:

A number of body systems are used when we are running. These systems include the nervous system, skeletal system, muscular system, respiratory system and the circulatory system. When we decide to run, a signal is sent from our brain to our muscles through the nervous system. Once the signal is received, our muscles starts to contract and we start running using our legs. The process of running uses a lot of energy and this energy is provided to us by cellular respiration. We use the respiratory system to bring oxygen into the body, where it interacts with food and generates energy. The carbon dioxide produced is removed by the respiratory system. The gases are transported throughout the body by our circulatory system. Thus, a number of body systems work in conjunction to enable a simple activity like running.

Hope this helps.

Gemiola [76]3 years ago
4 0

Answer:

Skeletal system, muscular system

Explanation:

Skeletal system:

bones

Muscular system:

muscles

Together, they work together and create the musculoskeletal system.

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DEFINITELY C

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3 years ago
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A machine produces a larger force than you exert to operate the machine. How does this input distance of the machine compare to
arlik [135]

Answer:

Because the output force is greater than the input force, the input distance must be greater than the output distance.

Explanation:

7 0
3 years ago
A cyclotron with a magnetic field of 0.47 t is designed to accelerate protons in a circle with a radius 0.68 m. What is the angu
Ghella [55]

The angular frequency of the cyclotron is 0.07 x 10^{8}Hz.

<h3>What is angular frequency?</h3>
  • Angular frequency, abbreviated "ω" is a scalar measure of rotation rate in physics.
  • It describes the rate of change of the argument of the sine function, the rate of change of the phase of a sinusoidal waveform, or the angular displacement per unit of time.
<h3>What is cyclotron?</h3>

The cyclotron device is made to accelerate charge particles to extremely high speeds by applying crossed electric and magnetic fields.

<h3>Calculation of angular frequency:</h3>

Given,

B = 0.47 T

r = 0.68

mass of proton = 1.6x10^{-27}

q = 1.6 x 10^{-19}

so, the frequency is:

f = qB/2\pim

f = 1.6 x 10^{-19} x 0.47/2x3.14x1.6x10^{-27}

f = 0.07 x 10^{8}

Hence, the angular frequency of the cyclotron is  0.07 x 10^{8}Hz.

Learn more about angular frequency here:

brainly.com/question/14244057

#SPJ4

7 0
1 year ago
Which of these chemical equations demonstrates the law of conservation of mass as it applies to the combustion of ethane? A. 2 C
WINSTONCH [101]

A. 2 C₂ H₆ + 7 O₂ → 4 C O₂ + 6 H₂ O


according to law of conservation of mass , the total mass of reactants side must be same as the total mass of product side. so we need to check if each atom in the equation has same number on both side of the equation or not.

in this equation , we have

4 atoms of carbon left and 4 atoms of carbon on right

12 atoms of hydrogen on left and 12 atoms of hydrogen on right

14 atoms of oxygen on left and 14 atoms of oxygen on right

3 0
3 years ago
A laser beam is incident at an angle of 30.0° from the vertical onto a solution of corn syrup in water. The beam is refracted to
dimaraw [331]

Answer with Explanation:

We are given that

Angle of incidence,i=30^{\circ}

Angle of refraction,r=19.24^{\circ}

a.Refractive index of air,n_1=1

We know that

n_2sinr=n_1sini

n_2=\frac{n_1sin i}{sin r}=\frac{sin30}{sin19.24}=1.517

b.Wavelength of red light in vacuum,\lambda=632.8nm=632.8\times 10^{-9} m

1nm=10^{-9} m

Wavelength in the solution,\lambda'=\frac{\lambda}{n_2}

\lambda'=\frac{632.8}{1.517}=417nm

c.Frequency does not change .It remains same in vacuum and solution.

Frequency,\nu=\frac{c}{\lamda}=\frac{3\times 10^8}{632.8\times 10^{-9}}

Where c=3\times 10^8 m/s

Frequency,\nu=4.74\times 10^{14}Hz

d.Speed in the solution,v=\frac{c}{n_2}

v=\frac{3\times 10^8}{1.517}=1.98\times 10^8m/s

5 0
3 years ago
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