Answer:
Explanation:
plate separation = 2.3 x 10⁻³ m
capacity C₁ = ε A / d
= ε A / 2.3 x 10⁻³
C₂ = ε A / 1.15 x 10⁻³
= ![\frac{2.3}{1.15}](https://tex.z-dn.net/?f=%5Cfrac%7B2.3%7D%7B1.15%7D)
a ) when charge remains constant
energy = ![\frac{q^2}{2C}](https://tex.z-dn.net/?f=%5Cfrac%7Bq%5E2%7D%7B2C%7D)
q is charge and C is capacity
energy stored initially E₁= ![\frac{q^2}{2C_1}](https://tex.z-dn.net/?f=%5Cfrac%7Bq%5E2%7D%7B2C_1%7D)
energy stored finally E₂ = ![\frac{q^2}{2C_2}](https://tex.z-dn.net/?f=%5Cfrac%7Bq%5E2%7D%7B2C_2%7D)
= ![\frac{2.3}{1.15}](https://tex.z-dn.net/?f=%5Cfrac%7B2.3%7D%7B1.15%7D)
= ![\frac{1.15}{2.3 } \times E_1](https://tex.z-dn.net/?f=%5Cfrac%7B1.15%7D%7B2.3%20%7D%20%5Ctimes%20E_1)
= ![\frac{1.15}{2.3 } \times 8.38](https://tex.z-dn.net/?f=%5Cfrac%7B1.15%7D%7B2.3%20%7D%20%5Ctimes%208.38)
= 4.19 J
b )
In this case potential diff remains constant
energy of capacitor = 1/2 C V²
energy is proportional to capacity as V is constant .
![\frac{E_2}{E_1} = \frac{C_2}{C_1}](https://tex.z-dn.net/?f=%5Cfrac%7BE_2%7D%7BE_1%7D%20%3D%20%5Cfrac%7BC_2%7D%7BC_1%7D)
![\frac{E_2}{8.38} = \frac{2.3}{1.15}](https://tex.z-dn.net/?f=%5Cfrac%7BE_2%7D%7B8.38%7D%20%3D%20%5Cfrac%7B2.3%7D%7B1.15%7D)
= 16.76 .
Answer:
The energy absorbed by the atomic electrons in the mercury atom is
J
Explanation:
Given:
Potential
V
According to the conservation law,
Loss in kinetic energy = Gain in potential energy
Here, energy absorbed by the atomic electrons is given by,
![E = eV](https://tex.z-dn.net/?f=E%20%3D%20eV)
Where
( charge of electron )
![E = 1.6 \times 10^{-19 } \times 4.9](https://tex.z-dn.net/?f=E%20%3D%201.6%20%5Ctimes%2010%5E%7B-19%20%7D%20%5Ctimes%204.9)
J
Therefore, the energy absorbed by the atomic electrons in the mercury atom is
J
I believe the answer is valcanos because they release sulfur in to the air and other chemicals so it willl affect the anispher
Answer:
It will cause kinetic energy to increase.
Explanation:
Given that Speed and Motion you went from the starting line to the finish line at different rates.
If you repeated the activity while carrying weights but keeping your times the same, the weight carried will add up to the mass of the body.
And since Kinetic energy K.E = 1/2mv^2
Increase in the mass of the body will definitely make the kinetic energy of the body to increase.
Since the time is the same, that means the speed V is the same.
Weight W = mg
m = W/g
The new kinetic energy will be:
K.E = 1/2(M + m)v^2
This means that there will be increase in kinetic energy.