Answer:
0.375 m/s north & 0.375 m/s east
Explanation:
Answer:
D = -4/7 = - 0.57
C = 17/7 = 2.43
Explanation:
We have the following two equations:

First, we isolate C from equation (2):

using this value of C from equation (3) in equation (1):

<u>D = - 0.57</u>
Put this value in equation (3), we get:

<u>C = 2.43</u>
This situation describes the Hooke's Law which states that "When an elastic object - such as a spring - is stretched, the increased length is called its extension. The extension of an elastic object is directly proportional to the force applied to it". The formula is <span>F = k × e , F for the force, k for spring constant expressed in N/m, e for extension in m. This equation works for as long the spring is not stretch too much because once it exceeded its limit, the spring will not return to its original length the moment the load is removed.</span>
Answer:
Final velocity, v = 0.28 m/s
Explanation:
Given that,
Mass of the model, 
Speed of the model, 
Mass of another model, 
Initial speed of another model, 
To find,
Final velocity
Solution,
Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :



V = 0.28 m/s
So, their final velocity is 0.28 m/s. Hence, this is the required solution.
To solve this problem it is necessary to apply the concepts related to
conservation of energy, for this case manifested through work and kinetic energy.


Where,
F= Force (Frictional at this case
)
d= Distance

Where,
m = mass
v = velocity
Equation both terms,




Replacing with our values we have that


Therefore the shortest distance in which the truck can come to a halt without causing the crate to slip forward relative to the truck is 49.05m