So the problem ask to calculate the magnitude of the average force applied to the ball if its mass is 0.2kg changes its velocity from 20m/s to 12m/s and the time contact with the ball with the wall is 60 ms. In my calculation the best answer would be 107N.
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Answer:
The change in momentum is 
Explanation:
From the question we are told that
The mass of the probe is 
The location of the prob at time t = 22.9 s is 
The momentum at time t = 22.9 s is 
The net force on the probe is 
Generally the change in momentum is mathematically represented as
The initial time is 22.6 s
The final time is 22.9 s
Substituting values
Answer:
<h2>0.245cm/min</h2>
Explanation:
The volume of the spherical balloon is expressed as V = 4/3πr³ where r is the radius of the spherical balloon. If the spherical balloon is inflated with gas at the rate of 500 cubic centimetres per minute then dV/dt = 500cm³.
Using chain rule to express dV/dt;
dV/dt = dV/dr*dr/dt
dr/dt is the rate at which the radius of the gallon is increasing.
From the formula, dV/dr = 3(4/3πr^3-1))
dV/dr = 4πr²
dV/dt = 4πr² *dr/dt
500 = 4πr² *dr/dt
If radius r = 40;
500 = 4π(40)² *dr/dt
500 = 6400π*dr/dt
dr/dt = 500/6400π
dr/dt = 5/64π
dr/dt = 0.245cm/min
Hence, the radius of the balloon is increasing at the rate of 0.245cm/min
Answer: The statement is false , if Jupiter and Venus somehow became the same size, Jupiter would still have more mass due to its density and composition and rocks, minerals, and etc.
Explanation:
