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zaharov [31]
4 years ago
10

Why is the objective lens of a refracting telescope so much larger than the eyepiece lens?

Physics
1 answer:
Over [174]4 years ago
5 0
Because the eyepiece lens just needs to refract off of the objective lens and so the objective lens needs to be bigger so you can see something from a distance I hope this helps

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A light spring with force constant 3.80 n/m is compressed by 7.20 cm as it is held between a 0.300-kg block on the left and a 0.
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4 years ago
A small space probe of mass 170 kg is launched from a spacecraft near Mars. It travels toward the surface of Mars, where it will
alukav5142 [94]

Answer:

The change  in momentum is  \Delta p =   kg \cdot m/s      

Explanation:

From the question we are told that  

       The mass of the probe is  m = 170 kg

       The location of the prob at time t = 22.9 s is  A  =

       The  momentum at time  t = 22.9 s is  p = < 51000, -7000, 0> kg m/s

        The net force on the probe is  F =  N

Generally the change in momentum is mathematically represented as

              \Delta p = F * \Delta t

The initial time is   22.6 s

 The final time  is  22.9 s

             Substituting values  

           \Delta p =  * (22.9 - 22.6)

            \Delta p =  * (0.3)  

              \Delta p =   kg \cdot m/s        

 

6 0
3 years ago
A spherical balloon is inflated with gas at the rate of 500 cubic centimeters per minute. How fast is the radius of the balloon
Nookie1986 [14]

Answer:

<h2>0.245cm/min</h2>

Explanation:

The volume of the spherical balloon is expressed as V = 4/3πr³ where r is the radius of the spherical balloon. If the spherical balloon is inflated with gas at the rate of 500 cubic centimetres per minute then dV/dt = 500cm³.

Using chain rule to express dV/dt;

dV/dt = dV/dr*dr/dt

dr/dt is the rate at which the radius of the gallon is increasing.

From the formula, dV/dr = 3(4/3πr^3-1))

dV/dr = 4πr²

dV/dt = 4πr² *dr/dt

500 =  4πr² *dr/dt

If radius r = 40;

500 = 4π(40)² *dr/dt

500 = 6400π*dr/dt

dr/dt = 500/6400π

dr/dt = 5/64π

dr/dt  = 0.245cm/min

Hence, the radius of the balloon is increasing at the rate of 0.245cm/min

8 0
3 years ago
Two objects of the same size will always have the same mass ? Is this statement correct
vlabodo [156]

Answer: The statement is false , if Jupiter and Venus somehow became the same size, Jupiter would still have more mass due to its density and composition and rocks, minerals, and etc.

Explanation:

8 0
3 years ago
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