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Burka [1]
3 years ago
9

Why is graphite used in pencil lead

Chemistry
1 answer:
ra1l [238]3 years ago
8 0

The bonds between the layers are much weaker than covalent bonds. This enables the layers to slide across each other, making graphite soft. Graphite can also conduct electricity, between the layers of carbon atoms. Graphite is used as pencil 'lead'.

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Which equation agrees with the ideal gas law?
photoshop1234 [79]
<span>\frac{(P1)(V1)}{T1}=\frac{(P2)(V2)}{T2} is directly related to the ideal gas law.

The ideal gas law states that:PV=nRT. Rewriting this gives:\frac{PV}{T}=nR. R is the universal gas constant, so its value is fixed. For a given sample, n is the number of moles of the gas, so its value would be fixed too. This means that the value of \frac{PV}{T} would be a fixed constant as well. Therefore, whatever the initial value \frac{(P1)(V1)}{T1} is, it should be equal to the final value \frac{(P2)(V2)}{T2}.</span>
6 0
3 years ago
Read 2 more answers
Lấy ví dụ về tính chất hoá học của chất
hodyreva [135]

Answer:

Ví dụ về tính chất hóa học bao gồm tính dễ cháy, tính độc, tính axit, khả năng phản ứng (nhiều loại) và nhiệt của quá trình cháy.

Explanation:

4 0
3 years ago
The K sp for barium fluoride, BaF2, is 2.45 × 10-5. What is the molar solubility of barium fluoride?
lilavasa [31]

Answer: The molar solubility of barium fluoride is 0.0183 moles/liter.

Explanation:

The equation for the reaction will be as follows:

BaF_2\rightarrow Ba^{2+}+2F^

By Stoichiometry,

1 mole of BaF_2 gives 2 moles of F^- and 1 mole of Ba^{2+}

Thus if solubility of BaF_2 is s moles/liter, solubility of Ba^{2+} is s moles/liter and solubility of F^- is 2s moles/liter

Therefore,  

K_sp=[Ba^{2+}][F^{-}]^2

2.45\times 10^{-5}=[s][2s]^2

4s^3=2.45\times 10^{-5}

s^3=6.12\times 10^{-6}moles/liter

s=0.0183moles/liter

Thus the molar solubility of barium fluoride is 0.0183 moles/liter.

8 0
4 years ago
You are provided with a beaker, wire, two nails, battery, bulb and dilute soultions of HCl, HNO3, alcohol and glucose. How will
trasher [3.6K]

Answer:

Acid solutions will be those which lights up a bulb when a circuit is connected through them.

Explanation:

Acid solutions such as HCl and HNO3 are polar in nature and permits the flow of electricity through them. Whereas non-polar solutions like ethanol and glucose solution will not allow the flow of electricity through them.

Therefore, when an electric circuit is completed by dipping the nails connected to a battery and a bulb into the different solutions, the lighting up of the bulb indicates which solutions are acids.

5 0
3 years ago
Need help please !!!
lianna [129]
With what do you need  help with 
8 0
4 years ago
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