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Alenkinab [10]
4 years ago
9

When Andrew began doing more residential home inspections than commercial building inspections, he found that his knowledge tran

sferred well when he inspected residential structures that had formerly served some sort of commercial purpose, such as an old factory that had been converted into an apartment building. He had a lot to learn, however, when inspecting residential structures that had been built as homes from the beginning. What is the most likely factor contributing to Andrew’s existing knowledge of building inspection?
whether the structure has served different purposes

how old the structure is

whether the structure has ever served a commercial purpose

how large the structure is
Engineering
1 answer:
inessss [21]4 years ago
7 0

Answer:

what are the answers

Explanation:

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3 years ago
A closed, rigid tank is filled with a gas modeled as an ideal gas, initially at 27°C and a gage pressure of 300 kPa. If the gas
ch4aika [34]

Answer:

gauge pressure is 133 kPa

Explanation:

given data

initial temperature T1 = 27°C = 300 K

gauge pressure = 300 kPa = 300 × 10³ Pa

atmospheric pressure = 1 atm

final temperature T2 = 77°C = 350 K

to find out

final pressure

solution

we know that gauge pressure is = absolute pressure - atmospheric pressure so

P (gauge ) = 300 × 10³ Pa - 1 × 10^{5} Pa

P (gauge ) = 2 × 10^{5} Pa

so from idea gas equation

\frac{P1*V1}{T1} = \frac{P2*V2}{T2}   ................1

so {P2} = \frac{P1*T2}{T1}

{P2} = \frac{2*10^5*350}{300}

P2 = 2.33 × 10^{5} Pa

so gauge pressure = absolute pressure - atmospheric pressure

gauge pressure = 2.33 × 10^{5}  - 1.0 × 10^{5}

gauge pressure = 1.33 × 10^{5} Pa

so gauge pressure is 133 kPa

4 0
3 years ago
g Design of a spindle present in an existing design needs to be reviewed for use under new loading needs. It is currently design
ss7ja [257]

Answer: its c

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Write in an Excel cell the appropriate @RISK function for a binomial distribution that results from 50 trials with probability o
borishaifa [10]

Answer:

Binomial Function

I got my output using the formula = 1 - BINOMDIST (17, 50, 0.3, TRUE)

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Explanation:

To draw a normal distribution:

1. Got to '@risk' and click on 'defined distribution'

2. Select 'binomial' in function block

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The use of @RISK to draw a binomial distribution of 50 trials and probability of success as 0.3 by entering formular =RISKBINOMIAL (50, 0.3).

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3 years ago
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