The volume of the balloon is approximately 2652 liters.
<h3>How to determine the volume occupied by the gas in a balloon </h3>
Let suppose that <em>flammable</em> hydrogen behaves ideally. GIven the molar mass (
), in kilograms per kilomole, and mass of the gas (
), in kilograms. The volume occupied by the gas (
), in cubic centimeters, is found by the equation of state for <em>ideal</em> gases:
(1)
Where:
- Ideal gas constant, in kilopascal-cubic meters per kilomole-Kelvin.
- Temperature, in Kelvin
- Pressure, in kilopascals
If we know that 
, 
, 
, 
and 
, then the volume of the balloon is:
(
)
The volume of the balloon is approximately 2652 liters. 
To learn more on ideal gases, we kindly invite to check this verified question: brainly.com/question/8711877
Explanation:
local winds are considered breezes while global winds produce mostly storms
Answer:
4) Van der waals forces
Explanation:
Krypton (Kr) belongs to the noble gas group and has fully filled valence orbitals. In the solid phase, Kr exists as a white solid with a face centered cubic structure.
Intermolecular forces of attraction from the strongest to the weakest include:
Ionic > hydrogen bonding > dipole-dipole > london dispersion
Kr is monoatomic and non-polar. When fully filled (stable) valence orbitals of 2 Kr atoms approach each other in close proximity they experience a repulsive force which prevents the formation of strong bonds. Thus, the only force of attraction in Kr is the long range weak Van Der Waals force also known as the london dispersion force.
Answer:
Scientific investigation aims to design and implement an experiment to learn new information, where
development aims to design a product to solve a problem.
Explanation:
CH3 is the empirical formula for the compound.
A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.
The number of atom or moles in the compound is
1.17 g C X 1 mol of C / 12.011 g C = 0.097411 mol of C.
0.287 g H x 1 mol of H / 1 g H = 0.28474 mol H.
This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.
So we can represent the compound with the formula C0.974H0.284.
Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.
we can divide 0.284 by 0.0974.
0.284 / 0.0974 = 3.
So here, Carbon is one and hydrogen is 3.
We can write the above formula as a CH3.
Hence the empirical formula for the sample compound is CH3.
For a detailed study of the empirical formula refer given link brainly.com/question/13058832.
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