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AleksAgata [21]
3 years ago
7

1. A dining hall had a total of 25 tables-some long rectangular tables and some round

Chemistry
1 answer:
TEA [102]3 years ago
7 0

x = 20 long tables

y = 5 round table

Explanation:

We have the following system of equations:

x + y = 25

8x + 6y = 190

From the first equation we have:

x = 25 - y

And we replace x in the second equation:

8(25 - y) + 6y = 190

200 - 8y + 6y = 190

200 - 2y = 190

200 - 190 = 2y

10 = 2y

y = 5

Now we insert the value of y in the next equation:

x = 25 - y

x = 25 - 5

x = 20

Learn more about:

system of equations

brainly.com/question/1748197

brainly.com/question/1658819

#learnwithBrainly

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Kinetic energy of an object is directly connected to the speed object. Like a toy car being used on a table, the toy car will speed up which means the kinetic energy of that toy car will also increase
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3 years ago
A sample of 211 g of iron (III) bromide is reacted with
Alisiya [41]

FeBr₃ ⇒ limiting reactant

mol NaBr = 1.428

<h3>Further explanation</h3>

Reaction

2FeBr₃ + 3Na₂S → Fe₂S₃ + 6NaBr

Limiting reactant⇒ smaller ratio (mol divide by coefficient reaction)

  • FeBr₃

211 g of Iron (III) bromide(MW=295,56 g/mol), so mol FeBr₃ :

\tt n=\dfrac{mass}{MW}\\\\n=\dfrac{211}{295,56}\\\\n=0.714

  • Na₂S

186 g of Sodium sulfide(MW=78,0452 g/mol), so mol Na₂S :

\tt n=\dfrac{186}{78.0452}=2.38

Coefficient ratio from the equation FeBr₃ :  Na₂S = 2 : 3, so mol ratio :

\tt FeBr_3\div Na_2S=\dfrac{0.714}{2}\div \dfrac{2.38}{3}=0.357\div 0.793

So  FeBr₃ as a limiting reactant(smaller ratio)

mol NaBr based on limiting reactant (FeBr₃) :

\tt \dfrac{6}{3}\times 0.714=1.428

6 0
3 years ago
What is the process by which molecules of water vapor in the air become liquid water?
mote1985 [20]
That is called condensation
5 0
3 years ago
If 1. 3618 moles of AsF3 are allowed to react with 1. 0000 mole of C2Cl6, what would be the theoretical yield of AsCl3, in moles
VARVARA [1.3K]

Answer:

AsF3:C2CI6

4:3

1.3618 moles: 1.02135 moles(1.3618÷4×3)

C2CI6 is the limting reagent

So the number of moles for AsCI3 is 0.817 moles( number of moles of the limting reagant) ÷3 ×4 (according to ratio by balancing chemical equation)=1.09 moles(3 s.f.)

or

Balanced equation

4AsF3 + 3C2Cl6 → 4AsCl3 + 3C2Cl2F4

Use stoichiometry to calculate the moles of AsCl3 that can be produced by each reactant.

Multiply the moles of each reactant by the mole ratio between it and AsCl3 in the balanced equation, so that the moles of the reactant cancel, leaving moles of AsCl3.

Explanation:

5 0
2 years ago
You have 34.1 x 1023 molecules of O2. How many moles of O2 do you have? Fill in the grid. Then, solve the problem and answer the
denis-greek [22]

Number of moles = 5.7 moles of oxygen.

<u>Explanation:</u>

We have to convert number of molecules into number of moles by dividing the number of molecules by Avogadro's number.

Here number of molecules of oxygen given is 34.1 × 10²³ molecules.

Now we have to divide the number of molecules by Avogadro's number as,

Number of moles = $\frac{number of molecules}{Avogadro's number}

                            = $\frac{34.1}{6.022} \times \frac{10^{23} }{10^{23} }

                          = 5.7 moles

So here molecules is converted into moles.

5 0
3 years ago
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