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dsp73
3 years ago
10

If you were asked to covert 1.3 mol al to atoms which of the following should you use for the concersion

Chemistry
1 answer:
Gnoma [55]3 years ago
4 0
1 mole/ (6.022x10^23)
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At a certain temperature the value of the equilibrium constant, Kc, is 1.27 for the reaction. 2As (s) + 3H2 (g) ⇌ 2AsH3 (g) What
Bess [88]

Answer:

0.887

Explanation:

Hello,

In this case, the law of mass action for the first reaction turns out:

Kc=\frac{[AsH_3]^2}{[As]^2[H_2] ^3}=1.27

Now, for the second reaction is:

Kc=\frac{[As][H_2] ^{3/2}}{[AsH_3]}

Therefore, by applying square root for the first reaction, one obtains:

\sqrt{Kc} =\sqrt{\frac{[AsH_3]^2}{[As]^2[H_2] ^3}} =\sqrt{1.27}

\frac{\sqrt{[AsH_3]^2} }{\sqrt{[As]^2} \sqrt{[H_2] ^3} } =\sqrt{1.27}

\sqrt{1.27}=\frac{[AsH_3]}{[As][H_2] ^{3/2}}

Finally, since Kc is asked for the inverse reaction, one modifies the previous equation as:

Kc'=\frac{1}{\sqrt{1.27} }=\frac{[As][H_2] ^{3/2}}{[AsH_3]}=0.887

Best regards.

8 0
3 years ago
Describe the solubility of water compared to ethanol?
Neko [114]
As you know ethanol is a an alcohol and alcohol is a hydrocarbon. Alcohol is made up of a carbon chain which Is always non polar and a OH group which is polar. According to the solubility rule like substances dissolves like substance. Using ethanol chemical formula. Ethanol has a 2 carbon chain and a OH group. water is polar so it will be attracted to the OH group. Carbon chain on the other hand is nonpolar so it will be repelled from the water.


Therefore the Solubility of alcohols is determined by the stronger of the two forces. The strength of the attraction of the OH group, and the amount of water they dissolve in.
4 0
2 years ago
Which shows two structures that are made mostly of metal?
lesya [120]

Answer:

The bell and the Eiffel tower

4 0
2 years ago
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What is the relationship between a cell and an organism?
alukav5142 [94]

Answer:

100%

Explanation:

Cell is the structural and functional unit of life. Without Cell, an organism can never be created.

6 0
2 years ago
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A copper cylinder, 12.0 cm in radius, is 44.9 cm long. If the density of copper is 8.90 g/cm^3, calculate the mass in grans of t
zlopas [31]

Answer:

we use: V = pi*(r^2)*h

V = 3.14*(12.0cm^2)*44.0 cm

V = 19895.04 cm^3

Therefore, mass = (8.90g/cm^3) * (19895.04 cm^3) = 177065.856 g

Explanation:

5 0
3 years ago
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