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jeka57 [31]
3 years ago
10

Acceleration is the rate at which happens

Physics
1 answer:
EastWind [94]3 years ago
4 0
Velocity and time inceases
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To determine the trajectory of the movement of a material point in the xOz plane that is subjected simultaneously to oscillation
nasty-shy [4]

We are to show that the given parametric curve is a circle.

The trajectory of a circle with a radius r will satisfy the following relationship:

(x-x_c)^2 + (y-y_c)^2 = r^2

(with (x_c,y_c) being the center point)

We are given the x and y in a parametric form which can be further rewritten (using properties of sin/cos):

x(t) = A\sin \pi(t+1) = A\sin (\pi t + \pi) = -A\sin \pi t\\y(t) = A\sin (\pi t + \frac{\pi}{2}) = A\cos \pi t

Squaring and adding both gives:

x^2(t) + y^2(t) = A^2(-1)^2\sin^2 \pi t + A^2 \cos^2 \pi t = A^2\\\implies x^2 + y^2 = A^2

The last expression shows that the given parametric curve is a circle with the center (0,0) and radius A.


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A tennis ball and a solid steel ball of the same diameter are dropped at the same time. Ignoring the air resistance effects, whi
Paha777 [63]
Yes I have the answer
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A 15 cm3 block of gold weighs 2.8 N. It is carefully submerged in a tank of mercury. One cm3 of mercury weighs 0.13 N.
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A horse began running due east and covered 25 km in 4.0 hr. What is the average velocity of the horse?
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<span>B) 6.25 km/hr due east </span>
3 0
3 years ago
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What is the current in a series circuit that has two resistors (4.0 ohms and 7.5 ohms) and a power source of 9.0 volts?
Olin [163]

-- First, we have to decide how to handle the two resistors.

The effective resistance of resistors in series is the sum
of their individual resistances.  That is, they act like a single
resistor, whose resistance is the sum of all of them.

So in this question, the 4.0 ohms and the 7.5 ohms act like a
single resistor of 11.5 ohms.

-- The current in the circuit is

                       (the supply voltage) / (the total resistance)

                   =                (9.0 volts)  /  (11.5 ohms)

                   =                      0.783... Ampere        (rounded)

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3 years ago
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