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Alexxandr [17]
3 years ago
9

How would playing a game of soccer, baseball, or basketball be different if inertia didn't exist?

Physics
1 answer:
BigorU [14]3 years ago
4 0
Inertia is what keeps everything moving, so if it didn't exist, the balls wouldn't keep going when they are kicked, or thrown.

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I need help quick pls . Its either physical or chemical change !
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Physical, chemical, chemical, physical, I’m pretty sure. Natural things, like you starting to breathe heavier are physical most of the time!!!
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Electric energy can be transferred into other types of energy we often experiences transformation of energy in our every day liv
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An amplifier.

Electrical energy provided to an amplifier is converted into sound energy as it is "fed" or provided to the speaker portion of an amplifier.

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Which type of heat transfer causes your face to feel warm when you sit in the sun?
MA_775_DIABLO [31]

Answer:

Radiation

Explanation:

The sun radiates energy to the earth to make it warmer near the equator.

6 0
3 years ago
Sketch the solid whose volume is given by the integral and evaluate the integral. $ \int_{0}^{{\color{red}6}}\int_{0}^{2\pi }\in
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Answer:

Explanation:

Attached is the evaluation

8 0
3 years ago
What is the distance that a car travels if it was brought to stop in 5 seconds and if it was traveling at 110 Km/h
Triss [41]

Answer:

Suppose that the acceleration is a constant, a.

a(t) = a.

To write the velocity equation, we must integrate over time, and the constant of integration will be equal to the initial velocity, in this case is 110km/h.

v(t) = a*t + 110km/h

And we know that at t = 5s, the car was brought to stop, so the velocity must be zero.

v(5s) = 0 = a*5s + 110km/h.

a = (110km/h)*(1/5s)

now we have that:

1 hour = 3600 seconds.

1km = 1000m

then:

110km/h = (110*1000/3600)m/s = 30.56 m/s

Then we have:

a = (-30.55 m/s)/5s = -6.11 m/s^2

Now the velocity equation is:

v(t) = -6.11m/s^2*t + 30.56m/s

To write the positon equation we must integrate over time again, we can get:

p(t) = (1/2)*(-6.11m/s^2)*t^2 + (30.56m/s)*t + p0

Where p0 is the initial position, here i will assume that is zero, because it does no really mater.

The total displacement of the car will be equal to p(5s)

p(5s) = (1/2)*(-6.11m/s^2)*(5s)^2 + (30.56m/s)*(5s) = 76.425 meters.

6 0
3 years ago
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