First I’ll show you this standard derivation using conservation of energy:
Pi=Kf,
mgh = 1/2 m v^2,
V = sqrt(2gh)
P is initial potential energy, K is final kinetic, m is mass of object, h is height from stopping point, v is final velocity.
In this case the height difference for the hill is 2-0.5=1.5 m. Thus the ball is moving at sqrt(2(10)(1.5))=
5.477 m/s.
Answer:
150153.06122 N
Explanation:
m = Mass of person = 75 kg
h = Height of fall = 1 m
g = Acceleration due to gravity = 9.81 m/s²
F = Force
s = Displacement = 0.49 cm
Potential energy is given by

Work is given by

The average force exerted is 150153.06122 N
False. it's depend on g -constant.
The parallel component is given by
F=180cos(25)=163.14N