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Fiesta28 [93]
2 years ago
6

25 POINTS please help!

Physics
2 answers:
salantis [7]2 years ago
7 0

Answer: b

Explanation:

kow [346]2 years ago
3 0

Answer:

b

Explanation:

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A child standing on the edge of a freely spinning merry-go-round moves quickly to the center. Which one of the following stateme
Komok [63]

Answer:

D

Explanation:

Why is because the merry go round wont do anything cause he will stay the same speed.

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3 years ago
If light intensity obeyed an inverse square law you would expect to find the intensity of light to decrease as the square of the
Reptile [31]
Inverse square law: \frac{I_{2} }{I_{1}}= (\frac{d{2} }{d_{1}})^2
where 
I_{1} is the intensity at distance 1
I_{2} is the intensity at distance 2
d_{1} is distance 1
d_{2} is distance 2

The inverse squared law state that intensity decreases in inverse proportion to the distance squared. So if light obeyed that rule, it will decreases its intensity as the square of the distance increases.

We can conclude that the correct answer is: true.
4 0
3 years ago
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For a two-level system, the weight of a given energy distribution can be expressed in terms of the number of systems, N, and the
Nikitich [7]

Answer:

W = N!/(n0! * n1!)

Explanation:

Let n0 = number of particles in the lowest energy state

n1 = number of particles in the excited energy state.

Using this, we can say that N = n0 + n1

From this we can then express the weight, W of the close system by finding the factorials of each particles

W = N!/(n0! * n1!)

Hence, the weight W is expressed as W = N!/(n0! * n1!)

7 0
2 years ago
What is an example of situational irony in the excerpt?​
Murrr4er [49]
Which excerpt are you talking about?
6 0
3 years ago
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A wooden block is sitting on an inclined plane near the bottom. The student gave the block a flick and it moved up the inclined
sladkih [1.3K]

Answer:

The block didn't slide due to balancing of gravitational force with friction force

Explanation:

When the block was given a flick the force provided an acceleration to it and it moved up the inclined plane. when the block reached top it was expected that it would slide back but it didn't this happened because of the frictional force acting on the bottom the block which was balancing the gravitational force component along the plane and this prevented sliding back of the block.

static friction  was balancing mg*sin(theta)

fs = mg*sin(theta)

6 0
2 years ago
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