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3 years ago

What is the correct name for the following compound: P2Br5

Chemistry

1 answer:

Ede4ka [16]3 years ago

7 0

Answer:

Diphosphorus pentabromide is the official name.

Explanation:

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A plane travels at 600 km/hr. How far will it travel in 3 hrs 15 min ?

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Answer:
1950 km in 3 hrs 15 min
step-by-step explanation:
600 • 3.25
1950 km

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3 years ago

What is the charge of a beta particle? 0 1– 2+ 4+

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3 years ago

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Which best describes thermal energy? It is the difference between internal energies of two or more substances. It is the sum of

Klio2033 [76]

Answer:

It is the portion of internal energy that can be transferred from one substance to another.

Explanation:

Thermal energy is the energy obtained by an object due to the motion of its particles.

It is also known as internal energy as it is the energy within the particles due to their motion.

Therefore, we can conclude that it is the portion of internal energy that can be transferred from one substance to another.

Hope this helps!

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4 years ago

Nitrogen (N) is much more electronegative than hydrogen (H). Which of the following statements is correct about the atoms in amm

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Answer: Option E. There are covalent bonds between the hydrogen atoms

Explanation:

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4 years ago

) Do you think the pH of 1,0 M tri-methyl ammonium (CH3)3NH+, pKa = 9.80, will be higher or lower than that of 1.0 M phenol, C6H

Elanso [62]

Answer:

1. The pH of 1.0 M trimethyl ammonium (pH = 1.01) is lower than the pH of 0.1 M phenol (5.00).

2. The difference in pH values is 4.95.

Explanation:

1. The pH of a compound can be found using the following equation:

$pH = -log([H_{3}O^{+}])$

First, we need to find [H₃O⁺] for trimethyl ammonium and for phenol.

Trimethyl ammonium:

We can calculate [H₃O⁺] using the Ka as follows:

(CH₃)₃NH⁺ + H₂O → (CH₃)₃N + H₃O⁺

1.0 - x x x

$Ka = \frac{[(CH_{3})_{3}N][H_{3}O^{+}]}{[(CH_{3})_{3}NH^{+}]}$

$10^{-pKa} = \frac{x*x}{1.0 - x}$

$10^{-9.80}(1.0 - x) - x^{2} = 0$

By solving the above equation for x we have:

x = 0.097 = [H₃O⁺]

$pH = -log([H_{3}O^{+}]) = -log(0.097) = 1.01$

Phenol:

C₆H₅OH + H₂O → C₆H₅O⁻ + H₃O⁺

1.0 - x x x

$Ka = \frac{[C_{6}H_{5}O^{-}][H_{3}O^{+}]}{[C_{6}H_{5}OH]}$

$10^{-10} = \frac{x^{2}}{1.0 - x}$

$1.0 \cdot 10^{-10}(1.0 - x) - x^{2} = 0$

Solving the above equation for x we have:

x = 9.96x10⁻⁶ = [H₃O⁺]

$pH = -log([H_{3}O^{+}]) = -log(9.99 \cdot 10^{-6}) = 5.00$

Hence, the pH of 1.0 M trimethyl ammonium is lower than the pH of 0.1 M phenol.

2. The difference in pH values for the two acids is:

$\Delta pH = pH_{C_{6}H_{5}OH} - pH_{(CH_{3})_{3}NH^{+}} = 5.00 - 1.01 = 4.95$

Therefore, the difference in pH values is 4.95.

I hope it helps you!

7 0

4 years ago