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DochEvi [55]
3 years ago
7

Is it correct to say that only one observable change accompanies a chemical change?

Chemistry
1 answer:
eimsori [14]3 years ago
5 0

Answer:

it is not correct to say that one observable change accompanies a chemical change because if a substance change its shape or size it doesn't mean that it has undergone a chemical change.

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Choose the number phrase that correctly matches the word phrase
nordsb [41]

Answer:

c

Explanation:

4 0
3 years ago
For Mn3+, write an equation that shows how the cation acts as an acid.
Mkey [24]

An acid is a compound which will give H+ ions or H3O^+  ions

the reaction will be

[Mn(H_{2}O )_{6} ^{+3} +H_{2}O --> [MnOH(H_{2}O)_{5}]^{+2} + H_{3}O^{+}

Thus as there is evolution of H_{3}O^{+} the Mn+3 is an acid

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3 years ago
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An order is received for ALternatGEL 30 cc PO q4h, ranitidine 150 mg PO bid, enteric-coated aspirin 325 mg PO qd, and tetracycli
kaheart [24]

Answer:

Tetracycline and antacid should not be given together.

Explanation:

In the given order, tetracycline and antacid are given together. The antacid is in the aspirin. The tetracycline and antacid should not be used together because the presence of antacid will suppress the effectiveness of the tetracycline. This is because antacid contains chemical compounds such as sodium bicarbonate which can interact with the tetracycline.

7 0
3 years ago
What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2 (formula weight = 164 g/mol) in 115 g of
Citrus2011 [14]

Answer:

freezing point   (°C) of the solution =  - 3.34° C

Explanation:

From the given information:

The freezing point (°C) of a solution can be prepared by using the formula:

\Delta T = iK_fm

where;

i = vant Hoff factor

the vant Hoff factor is the totality of the number of ions in the solution

Since there are 1 calcium ion and 2 nitrate ions present in Ca(NO3)2, the vant Hoff factor = 3  

K_f = 1.86 °C/m

m = molality of the solution and it can be determined by using the formula

molality = \dfrac{mole \ of \ solute }{kg \ of \ solvent }

which can now be re-written as :

molality = \dfrac{mole \ of \ Ca(NO_3)_2}{kg \ of \  water}

molality = \dfrac{\dfrac{mass \ of \  \ Ca(NO_3)_2}{molar \  mass of \ Ca(NO_3)_2} }{kg \ of \  water}

molality = \dfrac{\dfrac{11.3 \ g }{164 \ g/mol} }{0.115 \ kg }

molality = 0.599 m

∴

The freezing point (°C) of a solution can be prepared by using the formula:

\Delta T = iK_fm

\Delta T =3 \times (1.86 \ ^0C/m) \times (0.599 \ m)

\Delta T =3.34^0 \ C

\Delta T = the freezing point of water - freezing point of the solution

3.34° C = 0° C -  freezing point of the solution

freezing point  (°C) of the solution =  0° C - 3.34° C

freezing point   (°C) of the solution =  - 3.34° C

3 0
3 years ago
Is the caffeine molecule polar or non polar?
malfutka [58]
The caffeine molecule is a polar molecule.
7 0
3 years ago
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