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DochEvi [55]
3 years ago
7

Is it correct to say that only one observable change accompanies a chemical change?

Chemistry
1 answer:
eimsori [14]3 years ago
5 0

Answer:

it is not correct to say that one observable change accompanies a chemical change because if a substance change its shape or size it doesn't mean that it has undergone a chemical change.

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5Br−+BrO3−+6H+→3Br2+3H2O
sashaice [31]

Explanation :

The balanced chemical reaction is,

5Br^-+BrO_3^-+6H^+\rightarrow 3Br_2+3H_2O

The expression for the rates of consumption of the reactants are:

The rate of consumption of Br^- = -\frac{1}{5}\frac{d[Br^-]}{dt}

The rate of consumption of BrO_3^- = -\frac{d[BrO_3^-]}{dt}

The rate of consumption of H^+ = \frac{1}{6}\frac{d[H^+]}{dt}

The expression for the rates of formation of the products are:

The rate of consumption of Br_2 = +\frac{1}{3}\frac{d[Br_2]}{dt}

The rate of consumption of H_2O = +\frac{1}{3}\frac{d[H_2O]}{dt}

5 0
3 years ago
224/88Ra+4/2He+? find the missing isotope
andre [41]
Do u have a picture if so post it please
8 0
3 years ago
Calculate the atomic mass of Carbon if the two common isotopes of carbon have masses of
Mars2501 [29]

Answer:

Average atomic mass of carbon = 12.01 amu.

Explanation:

Given data:

Abundance of C¹² = 98.89%

Abundance of C¹³ = 1.11%

Atomic mass of C¹² = 12.000 amu

Atomic mass of C¹³ = 13.003 amu

Average atomic mass = ?

Solution:

Average atomic mass of carbon = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass of carbon = (12.000×98.89)+(13.003×1.11) /100

Average atomic mass of carbon=  1186.68 + 14.43333 / 100

Average atomic mass of carbon = 1201.11333 / 100

Average atomic mass of carbon = 12.01 amu.

5 0
3 years ago
A runner stood at the 100-meter mark on a track. When the timer started, the runner sprinted north to the 200-meter mark. It too
Olegator [25]

Answer:

8 m/s north

Explanation:

3 0
3 years ago
Read 2 more answers
Making methanol the element hydrogen is not abundant in nature, but it is a useful reagent in, for example, the potential synthe
stealth61 [152]
ΔG⁰ = ΔH⁰ - TΔS
ΔH⁰ = Hf,(CH₃OH) - Hf,(CO) = -238.7 + 110.5 = -128.2 kJ/mol
ΔS = S(CH₃OH) - S(CO) - 2S(H₂) = 126.8 - 197.7 - 2 x 130.6 = -332.1 J/mol.K
So 
ΔG⁰ = - 128200 + 332.1 T
For the reaction to be spontaneous:
ΔG⁰ < 0
So: -128200 + 332.1 T < 0
332.1 T < 128200
T < 386.028 K
5 0
3 years ago
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