C₆H₄(COOH)(COOK) + CsOH = C₆H₄(COOCs)(COOK) + H₂O
C₆H₄(COOH)(COO)⁻ + K⁺ + Cs⁺ + OH⁻ = C₆H₄(COO)₂²⁻ + K⁺ + Cs⁺ + H₂O
C₆H₄(COOH)(COO)⁻ + OH⁻ = C₆H₄(COO)₂²⁻ + H₂O
Answer is: 13181,7 kJ of energy <span>is released when 10.5 moles of acetylene is burned.
</span>Balanced chemical reaction: C₂H₂ + 5/2O₂ → 2CO₂ + H₂O.
<span>ΔHrxn = sum of
ΔHf (products of reaction) - sum of ΔHf (reactants).</span><span>
Or ΔHrxn = ∑ΔHf (products of reaction)
- ∑ΔHf (reactants).
ΔHrxn - enthalpy change of chemical reaction.
<span>ΔHf - enthalpy of formation of reactants or
products.
</span></span>ΔHrxn = (2·(-393,5) + (-241,8)) - 226,6 · kJ/mol.
ΔHrxn = -1255,4 kJ/mol.
Make proportion: 1 mol (C₂H₂) : -1255,4 kJ = 10,5 mol(C₂H₂) : Q.
Q = 13181,7 kJ.
D increase in temperature and increase in pressure.
