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Ronch [10]
3 years ago
6

Propose a situation where friction is undesirable.

Physics
1 answer:
Naddik [55]3 years ago
6 0
Trying to move a large object such as a furniture piece across carpet.
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When a rigid body rotates about a fixed axis, all the points in the body have the same A. centripetal acceleration B. tangential
Leto [7]

Answer:

The angular acceleration is same at all the points in the body.

Option (D) is correct.

Explanation:

Given:

When a rigid body rotates about a fixed axis, all the points in the body have the same,

For finding which quantity is same we use pure rotational concept,

 v = \omega r

Where \omega = angular frequency, r = radius of rigid body

When a rigid body rotates about a fixed axis angular velocity of all the points in the body are same.

But the tangential speed, tangential acceleration, linear displacement, and centripetal acceleration depend on the position of the points and hence they are not the same.

Therefore, the angular acceleration is same at all the points in the body.

8 0
3 years ago
Which sphere does the frog belong to?
LiRa [457]

Answer:

what

Explanation:

3 0
4 years ago
Two parallel plates are a distance apart with a potential difference between them. A point charge moves from the negatively char
IgorC [24]

Answer:

K' = 1200 J

Explanation:

To find the kinetic energy you first take into account the formula for the kinetic energy of the charge:

K=\frac{1}{2}mv^2 = 800J   (1)

m: mass of the charge

v: final speed of the charge when it reaches the positively charged plate.

Furthermore, you have that the acceleration of the charge is obtained by using the second Newton law:

F=ma=qE\\\\a=\frac{qE}{m} (2)

a: acceleration

E: electric field

q: charge

The electric field between two parallel plates is V/d, being V the potential difference and d the separation between plates. You replace E in (2) and obtain:

a=\frac{qV}{md}

Next, you take into account the following formula for the calculation of the final speed of the charge:

v^2=v_o^2+2ad\\\\v_o=0m/s\\\\v=\sqrt{\frac{2qVd}{md}}=\sqrt{\frac{2qV}{m}}

Next, you replace this value of v in (1):

K=\frac{1}{2}mv^2=\frac{1}{2}m(\frac{2qV}{m})=qV = 880J   (3)

If the distance between plates is tripled, and the potential difference is halved, you have for the new final speed:

v'^2=v'_o^2+2a(3d)\\\\v_o=0m/s\\\\v'=\sqrt{6ad}=\sqrt{6(\frac{q}{md})\frac{V}{2}d}=\sqrt{\frac{3qV}{m}}

And the kinetic energy becomes:

K'=\frac{1}{2}mv^2=\frac{1}{2}m(\frac{3qV}{m})=\frac{3}{2}qV    (4)

You calculate the ratio between both kinetic energies K and K', that is, you divide equations (3) and (4), in order to find the new kinetic energy:

K=qV=800J\\\\K'=\frac{3}{2}qV\\\\\frac{K}{K'}=\frac{qV}{3/2\ qV}=\frac{2}{3}\\\\K'=\frac{3}{2}K=\frac{3}{2}(800J)=1200J

hence, the kinetic energy of the charge incresases to 1200J

4 0
3 years ago
..................................
sammy [17]

Hi, what is it you need help with?

8 0
2 years ago
A person travels by car from one city to another with different constant speeds between pairs of cities. she drives for 50.0 min
liraira [26]
I think it's 45 miles. Don't know for sure though
3 0
3 years ago
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