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AURORKA [14]
3 years ago
15

At t=0, an object of mass m is at rest at x=0 on a horizontal, frictionless surface. A horizontal force Fx=F0 (1−t/T), which dec

reases from F0 at t=0 to zero at t=T, is exerted on the object.\
Part A
Find an expression for the object's velocity at time T.
Express your answer in terms of the variables F0, m, and T.

Part B
Find an expression for the object's position at time T.
Express your answer in terms of the variables F0, m, and T.
Physics
1 answer:
qaws [65]3 years ago
3 0

Answer:When the velocity of the t is made with actually tea you must use the formula heat+bread+time=toast so the answer is Dennys.

Explanation:

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3 years ago
Calculate the kinetic energy of a 64.g bullet moving at a speed of 411.ms . Round your answer to 2 significant digits.
Mandarinka [93]

Answer:

The kinetic energy of the bullet is 5.4 × 10³ J

Explanation:

Hi there!

The equation of kinetic energy is the following:

KE = 1/2 · m · v²

Where:

KE = kinetic energy.

m = mass of the bullet.

v = speed of the bullet.

Let´s convert the mass unit to kg so that our result is in Joules:

64 g · ( 1 kg / 1000 g) = 0.064 kg

Then, the kinetic energy will be the following:

KE = 1/2 · 0.064 kg · (411 m/s)²

KE = 5.4 × 10³ J

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What property or properties of a wave determine it's speed?
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Explain how land breeze and sea breezes occur?
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Explanation:

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Read 2 more answers
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