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Roman55 [17]
3 years ago
8

Help Please

Physics
1 answer:
hichkok12 [17]3 years ago
8 0
Gravitational potential energy i think
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A 30⁰ 5.2 km 3.7 km FIGURE 1 40⁰ B x FIGURE 1 shows two displacement vector A and B. Determine the magnitude and direction of th
Alika [10]

The resulatant displacement will be 8.60m

What is displacement?

Displacement is the shortest path covered by an individual.

We have given the distance 5.2km and 3.7Km.

The resultant will be given in the photo



to learn more about displacement click brainly.com/question/13413762

8 0
2 years ago
Un contenedor de 1800 N está en reposo sobre un plano inclinado a 28°, el coeficiente de fricción entre el contenedor y el plano
babunello [35]

Answer:

F = 1480.77N

Explanation:

In order to calculate the required force to push the container with a constant velocity, you take into account the the sum of force on the container is equal to zero. Furthermore, you have for an incline the following sum of forces:

F-Wsin\alpha-F_r=0\\\\F-Wsin\alpha-N\mu cos\alpha=0\\\\F-Wsin\alpha-W\mu cos\alpha=0     (1)

F: required force = ?

W: weight of the container = 1800N

N: normal force = weigth

α: angle of the incline = 28°

g: gravitational acceleration = 9.8m/s^2

μ: coefficient of friction = 0.4

You solve the equation (1) for F and replace the values of the other parameters:

F=W(sin\alpha+\mu cos\alpha)\\\\F=(1800N)(sin28\°+(0.4)cos28\°)=1480.77N

The required force to push the container for the incline with a constant velocity is 1480.77N

8 0
3 years ago
1. How many paths through which charge can flow would be shown in a diagram of a series
Elanso [62]
1. One
2. Oohm


Hope this helps
5 0
3 years ago
14. A group of students tested different materials in an electric circuit. The table shows the results of their experiment.
kvasek [131]

Answer: There is no pic homie

Explanation:I am on the same question, so I can’t help :(

8 0
3 years ago
Uniform, identical bricks 20 cm long are stacked so that 4 cm of each brick extends beyond the brick beneath. How many bricks ca
Butoxors [25]

Answer:

6 bricks

Explanation:

For the bricks system to NOT fall over, then the center of mass of the system must lie within the touching area of the bottom brick.

Let the reference line be at the left end of the base brick, and the bricks are being stacking to the right direction.

- The 1st brick would have a center of mass at 20/2 = 10 cm or 10 + 0, this is < 20 cm so it stays

- 2 stacked bricks would have a center of mass at (10 + 14)/2 = 12 cm or 10 + 2, this is also < 20 cm so it stays

- 3 stacked bricks would have a center of mass at (10 + 14 + 18) / 3 = 14 cm or 10 + 2*2, this is also < 20 cm so it stays

- 4 stacked bricks would have a center of mass at (10 + 14 + 18 + 22)/4 = 16 cm or 10 + 2*3, this is also < 20 cm so it stays

- 5 stacked bricks would have a center of mass at (10 + 14 + 18 + 22 + 26)/5 = 18 cm or 10 + 2*4, this is also < 20 cm so it stays

- 6 stacked bricks would have a center of mass at (10 + 14 + 18 + 22 + 26 + 28)/5 = 20 cm or 10 + 2*5, this is also <= 20 cm so it stays before tipping over.

- The 7th brick would make everything fall down.

4 0
4 years ago
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