A car start from rest and reached with a speed of 20m/s in 9seconds calculate the acceleration of the car and calculate the disp
1 answer:
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Explanation:
It is given that,
Mass of a bungee jumper is 65 kg
The time period of the oscillation is 38 s, hitting a low point eight more times.It means its time period is
After many oscillations, he finally comes to rest 25.0 m below the level of the bridge.
For an oscillating object, the time period is given by :
k = spring stiffness constant
So,
When the cord is in air,
mg=kx
x = the extension in the cord
So, the unstretched length of the bungee cord is equal to 25 m - 5.6 m = 19.4 m
Answer:
1.39 × 10⁻¹³ electrons were transferred
Explanation:
Given:
Charge on electroscope = - 2.0 μC
charge on finger = 2.7 μC
Now,
The net charge when in contact
= Charge on electroscope + charge on finger
or
The net charge when in contact = - 2.0 μC + 2.7 μC = 0.7 μC
Also,
Charge on the electroscope and the finger is same
thus,
The charge on the electroscope =
or
The charge on the electroscope =
or
The charge on the electroscope = 0.35 μC
Now,
The change in charge on the electroscope
= Final charge - Initial charge on the electroscope
= 0.35 μC - (- 2.0 μC)
or
The change in charge on the electroscope = 2.35 μC
also,
Charge = Number of electrons × Charge on an electron
or
2.35 μC = Number of electron × 1.69 × 10⁻¹⁹ C
or
2.35 × 10⁻⁶ C = Number of electron × 1.69 × 10⁻¹⁹ C
or
Number of electron =
or
Number of electron = 1.39 × 10⁻¹³ electrons were transferred.