Answer:
(a) Angular speed will be 0.2512 rad/sec
(b) Radius will be 213.375 m
Explanation:
We have given time to complete 1 lap = 25 sec
We know that 1 lap =
radian
(a) So angular speed 
(B) Tangential velocity is given as v = 53.6 m/sec
We know that tangential velocity is given by

So radius 
<h2>Right answer: It follows a curved path
</h2>
The movement of a projectile is a movement in two dimensions (forming a curved path: a parabola shape) with <u>constant acceleration.
</u>
<u>
</u>
A projectile is any body or object that is thrown or projected by means of some force and continues in motion by its own inertia. This means the only force that acts on it while in motion is <u>the acceleration of gravity</u> (in this case we are on Earth, so the gravity value is
).
Where gravity influences the <u>vertical movement</u> of the projectile, while <u>the horizontal movement</u> of the projectile is the result of the tendency of any object to remain in motion at a constant speed (according to Newton's 1st law of motion sometimes called Law of Inertia).
The other options are <u>incorrect</u> because are <u>false</u>:
-The forward motion negates air resistance: There is always at least a small percent of air resistance, as long as that movement is done on Earth.
-It has variable acceleration: In projectile motion acceleration is constant (gravity acceleration)
.
-It is unaffected by gravity: The only force that acts on the projectile is due gravity.
The answer is C atleast thats what i'm gonna put but i'll come correct it if i'm wrong
Answer:
a) 
b) 
c) 
Explanation:
From the exercise we know the initial velocity of the projectile and its initial height

To find what time does it take to reach maximum height we need to find how high will it go
b) We can calculate its initial height using the following formula
Knowing that its velocity is zero at its maximum height



So, the projectile goes 1024 ft high
a) From the equation of height we calculate how long does it take to reach maximum point



Solving the quadratic equation



So, the projectile reach maximum point at t=2s
c) We can calculate the final velocity by using the following formula:


Since the projectile is going down the velocity at the instant it reaches the ground is:

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