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Mumz [18]
3 years ago
12

What does ultraviolet light from the sun do with oxygen gas.

Chemistry
1 answer:
g100num [7]3 years ago
3 0

Answer:

Gases in Earth's atmosphere form a protective layer

Nitrogen, oxygen and ozone molecules in the upper atmosphere and stratosphere absorb ultraviolet light from the Sun, providing a shield that prevents this radiation from passing to the Earth's surface.

Explanation:

i got this from  

...www.aeronomie.be

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Brainiest plsss helpp
svlad2 [7]

Answer:

\boxed {\boxed {\sf  A. \ 19,320 \ kg/m^3}}

Explanation:

We want to find the density. The formula is mass over volume.

\rho = \frac{m}{v}

The mass is 500 kilograms. The volume is 0.026 cubic meters.

m= 500 \ kg \\v=0.026 \ m^3

Substitute the values into the formula.

\rho= \frac{ 500 \ kg}{ 0.026 \ m^3}

Divide.

\rho = 19230.7692 \ kg/m^3

This is just about equal to 19,320 kg/m³, so choice A is correct.

3 0
2 years ago
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For problems 2 & 3, the density of the sample is 0.9977 g/mL and the molar mass of calcium carbonate is 100.0 g/mol. 2. Calc
Alenkasestr [34]
1) Use of density formula to calculate mass of sample, M

D = M / V => M = D* V = 0.9977 g / mL * 50.00 mL = 49.885 g of sample

Realize that the sample is the solution.

2) Use ppm concentration to calculate mass of solute (calcium carbonate)

By definition, 75.0 ppm = 75.0 g of calcium carbonate / 1,000,000 g of solution.

You use that ratio to calculate the mass of calcium carbonate in 49.885 g of solution.

Mass of solute = 49.885 g of solution * [75.0 g of calcium carbonate] / [1,000,000 g of solution] =

Mass of solute =  0.00374 g of calcium carbonate

Answer: 0.00374 g of calcium carbonate
4 0
3 years ago
Based on the hierarchical organization, order these terms from smallest to largest.
erik [133]
From smallest to largest it will be first Carbon,Water,Carbohydrate,Mitochondria, Skin Cell.
4 0
3 years ago
Read 2 more answers
Extra points & brainlest to anyone that can help me with both answers
ki77a [65]

Answer:

1st blank: Organelles

2nd blank: Plant

3rd blank: chloroplasts

3 0
3 years ago
PLEASE HELP!!!!!!!
dsp73

Answer: 1. 2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu

2. 3 moles of CuCl_2 : 2 moles of Al

3. 0.33 moles of CuCl_2 : 0.92 moles of Al

4. CuCl_2 is the limiting reagent and Al is the excess reagent.

5. Theoretical yield of AlCl_3 is 29.3 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al=\frac{25.0g}{27g/mol}=0.92moles

\text{Moles of} CuCl_2=\frac{45.0g}{134g/mol}=0.33moles

The balanced chemical equation is:

2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu  

According to stoichiometry :

3 moles of CuCl_2 require = 2 moles of Al

Thus 0.33 moles of CuCl_2 will require=\frac{2}{3}\times 0.33=0.22moles  of Al

Thus CuCl_2 is the limiting reagent as it limits the formation of product and Al is the excess reagent.

As 3 moles of CuCl_2 give = 2 moles of AlCl_3

Thus 0.33 moles of CuCl_2 give =\frac{2}{3}\times 0.33=0.22moles  of AlCl_3

Theoretical yield of AlCl_3=moles\times {\text {Molar mass}}=0.22moles\times 133.34g/mol=29.3

Thus 29.3 g of aluminium chloride is formed.

5 0
2 years ago
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