Answer:
Explanation:
We want to find the density. The formula is mass over volume.
The mass is 500 kilograms. The volume is 0.026 cubic meters.
Substitute the values into the formula.
Divide.
This is just about equal to 19,320 kg/m³, so choice A is correct.
1) Use of density formula to calculate mass of sample, M
D = M / V => M = D* V = 0.9977 g / mL * 50.00 mL = 49.885 g of sample
Realize that the sample is the solution.
2) Use ppm concentration to calculate mass of solute (calcium carbonate)
By definition, 75.0 ppm = 75.0 g of calcium carbonate / 1,000,000 g of solution.
You use that ratio to calculate the mass of calcium carbonate in 49.885 g of solution.
Mass of solute = 49.885 g of solution * [75.0 g of calcium carbonate] / [1,000,000 g of solution] =
Mass of solute = 0.00374 g of calcium carbonate
Answer: 0.00374 g of calcium carbonate
From smallest to largest it will be first Carbon,Water,Carbohydrate,Mitochondria, Skin Cell.
Answer: 1. 
2. 3 moles of 
: 2 moles of 
3. 0.33 moles of : 0.92 moles of
4. is the limiting reagent and is the excess reagent.
5. Theoretical yield of 
is 29.3 g
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
3 moles of require = 2 moles of
Thus 0.33 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 3 moles of give = 2 moles of
Thus 0.33 moles of give = of
Theoretical yield of 
Thus 29.3 g of aluminium chloride is formed.
