Answer:
The pressure of the gas would be 3.06 atm
Explanation:
Amonton's law states that the pressure is directly proportional to the absolute temperature of a gas under constant volume. The equation is:
P1 / T1 = P2 / T2
<em>Where P1 is the initial pressure = 3.16atm</em>
<em>T1 is initial absolute temperature = 273.15 + 32.2°C = 305.35K</em>
<em>P2 is our incognite</em>
<em>And T2 is = 273.15 + 22.9°C = 296.05K</em>
<em />
Replacing:
3.16atm / 305.35K = P2 / 296.05K
3.06 atm = P2
<h3>The pressure of the gas would be 3.06 atm</h3>
Empirical formula is the simplest ratio of components making up a compound.
The percentage composition of each element has been given
therefore the mass present of each element in 100 g of compound is
B N H
mass 40.28 g 52.20 g 7.53 g
number of moles
40.28 g / 11 g/mol 52.20 g / 14 g/mol 7.53 g / 1 g/mol
= 3.662 mol = 3.729 mol = 7.53 mol
divide the number of moles by the least number of moles, that is 3.662
3.662 / 3.662 3.729 / 3.662 7.53 / 3.662
= 1.000 = 1.018 = 2.056
the ratio of the elements after rounding off to the nearest whole number is
B : N : H = 1 : 1 : 2
therefore empirical formula for the compound is B₁N₁H₂
that can be written as BNH₂
102 grams of ammonia is formed when 3 moles of nitrogen and 6.7 moles of hydrogen reacts.
Explanation:
The equation given is of Haeber's process in which the nitrogen is limiting factor in the ammonia formation and hydrogen if in excess gets delimited.
We know that 1 mole of Nitrogen gives 2 moles of ammonia.
We have 3 moles of nitrogen here,
So, 6 moles of ammonia will be form
so from the formula
no of moles=mass/atomic mass
mass= no. of moles*atomic mass
= 6*17
= 102 grams of ammonia will be formed.
So, 6 moles or 102 grams of ammonia is formed when 3 mole of nitrogen and 6.7 mole of hydrogen reacts.
