Answer:
(C) calcNewPrice(oldPrice, &newPrice);
Explanation:
It's a void function so there's no return value, however they wanted to change a value. The only way to do that is to pass in an address of the variable into the function, and deference it and store the new data there.
Answer:
(d) 2996 kJ
Explanation:
We have given initial volume 
initial pressure 
initial temperature 
we know that during isothermal process the work done is given by
where 
putting all these value in formula of work done
=-2995.8 kJ here negative sign indicates that work is dine on the gas
so wok done =2995.8 kJ
Answer and Explanation:
It is True that packet size increases the transmission time of the packets. This is because packet transmission would be impacted depending on the packet size, whether it is large or small. Here comes the concept of bandwidth of the medium. For a particular bandwidth of the medium, if the packet is small then many such packets can pass through the medium at a given time, rather than less packets at a given time when the packet sizes are larger. Transmission time of a packet = Packet size / Bandwidth of the medium.
If the bandwidth is high, the transmission time will be less. Also, if the packet size increases then, as we saw above the transmission time will increase.
Every packet has to have a header information in which there will be several information and data about the packet and the protocol it follows, also what is the source and destination of the packet. The information contained in the header of a packet may vary in case of different protocols. The address portion of the packet is a overhead but us actually necessary when the packet needs to be transferred from a source to a destination using a protocol. The size of the header varies from protocol to protocol and is an overhead and has impact on data transmission rates since size of the packet increases because of the header.
Answer:
isentropic efficiency of the compressor (nc)=
89.4%
Explanation:
answer attached
