Answer:
a. 0.4544 N
b. ![5.112 \times 10^{-5 M}](https://tex.z-dn.net/?f=5.112%20%5Ctimes%2010%5E%7B-5%20M%7D)
Explanation:
For computing the normality and molarity of the acid solution first we need to do the following calculations
The balanced reaction
![H_2SO_4 + 2NaOH = Na_2SO_4 + 2H_2O](https://tex.z-dn.net/?f=H_2SO_4%20%2B%202NaOH%20%3D%20Na_2SO_4%20%2B%202H_2O)
![NaOH\ Mass = Normality \times equivalent\ weight \times\ volume](https://tex.z-dn.net/?f=NaOH%5C%20Mass%20%3D%20Normality%20%5Ctimes%20equivalent%5C%20weight%20%5Ctimes%5C%20volume)
![= 0.3200 \times 40 g \times 21.30 mL \times 1L/1000mL](https://tex.z-dn.net/?f=%3D%200.3200%20%5Ctimes%2040%20g%20%5Ctimes%2021.30%20mL%20%5Ctimes%20%201L%2F1000mL)
= 0.27264 g
![NaOH\ mass = \frac{mass}{molecular\ weight}](https://tex.z-dn.net/?f=NaOH%5C%20mass%20%3D%20%5Cfrac%7Bmass%7D%7Bmolecular%5C%20weight%7D)
![= \frac{0.27264\ g}{40g/mol}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.27264%5C%20g%7D%7B40g%2Fmol%7D)
= 0.006816 mol
Now
Moles of
needed is
![= \frac{0.006816}{2}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.006816%7D%7B2%7D)
= 0.003408 mol
![Mass\ of\ H_2SO_4 = moles \times molecular\ weight](https://tex.z-dn.net/?f=Mass%5C%20of%5C%20H_2SO_4%20%3D%20moles%20%5Ctimes%20molecular%5C%20weight)
![= 0.003408\ mol \times 98g/mol](https://tex.z-dn.net/?f=%3D%200.003408%5C%20mol%20%5Ctimes%2098g%2Fmol)
= 0.333984 g
Now based on the above calculation
a. Normality of acid is
![= \frac{acid\ mass}{equivalent\ weight \times volume}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bacid%5C%20mass%7D%7Bequivalent%5C%20weight%20%5Ctimes%20volume%7D)
![= \frac{0.333984 g}{49 \times 0.015}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.333984%20g%7D%7B49%20%5Ctimes%200.015%7D)
= 0.4544 N
b. And, the acid solution molarity is
![= \frac{moles}{Volume}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bmoles%7D%7BVolume%7D)
![= \frac{0.003408 mol}{15\ mL \times 1L/1000\ mL}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.003408%20mol%7D%7B15%5C%20mL%20%5Ctimes%20%201L%2F1000%5C%20mL%7D)
= 0.00005112
=![5.112 \times 10^{-5 M}](https://tex.z-dn.net/?f=5.112%20%5Ctimes%2010%5E%7B-5%20M%7D)
We simply applied the above formulas
I think it’s structural engineers but still check with the others
Answer:
Hydrostatic force = 41168 N
Explanation:
Complete question
A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water so that the top is 4 ft below the surface. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)
Let "x" be the side length submerged in water.
Then
w(x)/base = (4+3-x)/altitude
w(x)/5 = (4+3-x)/3
w(x) = 5* (7-x)/3
Hydrostatic force = 62.5 integration of x * 4 * (10-x)/3 with limits from 4 to 7
HF = integration of 40x - 4x^2/3
HF = 20x^2 - 4x^3/9 with limit 4 to 7
HF = (20*7^2 - 4*7^(3/9))- (20*4^2 - 4*4^(3/9))
HF = 658.69 N *62.5 = 41168 N
Answer:
Otto engine
Explanation:
As we know that
Power = Torque x speed
So we can say that when speed of engine then power of engine also will increases.
The speed of Otto engine is more as compare to Diesel engine so the power of Otto engine is more.But on the other hand torque of Diesel engine is more as compare to Otto engine but the speed is low so the product of speed and torque is more for Otto engine .It means that when requires large amount of power then Otto engine should be use.