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olga2289 [7]
3 years ago
9

Samantha and Emily are pushing a box of textbooks in the same direction across their classroom. Samantha is applying a force of

10 newtons, and Emily is applying a force of 10 newtons. What is the net force of their efforts?
Physics
1 answer:
velikii [3]3 years ago
3 0

Answer: 20 newtons

Explanation:

Given that:

Force applied by Samantha = 10 newtons

Force applied by Emily = 10 newtons

Direction of both forces = same

Net force of their efforts = ?

Since net force of forces applied in the same direction is obtained by adding up the seperate forces applied, then

Net force = (10 newtons + 10 newtons)

Net force = 20 newtons

Thus, the net force of their efforts is 20 newtons.

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A 100g block is initially compressing a spring 5.0 cm. The spring launches the block 50cm horizontally along the ground with a f
Setler [38]

Answer:

7200 N/m

Explanation:

Metric unit conversion

100g = 0.1 kg

5 cm = 0.05 m

50 cm = 0.5 m

As the block is released from the spring and travelling to height h = 1.5m off the ground, the elastics energy is converted to work of friction force and the potential energy at 1.5 m off the ground

The work by friction force is the product of the force F = 15N itself and the distance s = 0.5 m

W_f = F_fs = 15*0.5 = 7.5 J

Let g = 10 m/s2. The change in potential energy can be calculated as the following:

E_p = mgh = 0.1*10*1.5 = 1.5 J

Therefore, as elastic energy is converted to potential energy and work of friction:

E_e = W_f + E_p

kx^2/2 = 7.5 + 1.5 = 9 J

k = 9*2/x^2 = 18/0.05^2 = 7200 N/m

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3 years ago
Write down the principal of lever​
pashok25 [27]

Answer:

See the explanation below.

Explanation:

A lever is a simple machine that changes the magnitude and direction of the force applied to move an object. Minimizes the force needed to lift the object.

By means of the following image, we can see the principle of operation of a lever.

The load can be moved thanks to the force multiplied by the distance to the fulcrum.

3 0
3 years ago
A go-cart and rider have a mass of 14 kg. If the cart accelerates at 6m/s^2 during a 40 m sprint in 100 seconds, how much power
lara [203]

Answer:

P = 33.6 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces [N]

m = mass = 14 [kg]

a = acceleration = 6 [m/s²]

F = 14*6\\F = 84 [N]

In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.

W = F*d

where:

W = work [J]

F = force = 84 [N]

d = displaciment = 40 [m]

W = 84*40\\W = 3360 [J]

Finally, the power can be calculated by the relationship between the work performed in a given time interval.

P=W/t\\

where:

P = power [W]

W = work = 3360 [J]

t = time = 100 [s]

Now replacing:

P=3360/100\\P=33.6[W]

The power is given in watts

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What three things are needed for a mechanical wave
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