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Nady [450]
3 years ago
5

The oxidation of pyruvate is not the only process that generates acetyl-CoA. In particular, fatty acids are broken down through

oxidation, generating a great deal of acetyl-CoA, which can also enter the TCA cycle to generate high energy molecules. Is there a difference between between the TCA cycle using acetyl-CoA generated from fatty acid oxidation compared to that generated from carbohydrate oxidation?
A. The concentration of malate increases when reacting with acetyl-CoA derived from a fatty acid,
B. A molecule of acetyl-CoA derived from a fatty acid generates more FADH2 than acetyl-CoA from
C. A molecule of acetyl-CoA derived from a carbohydrate generates more NADH than acetyl-CoA but not when reacting with acetyl-CoA derived from a carbohydrate. WI derived from a carbohydrate derived from a fatty acid.
D. There is no difference in the TCA cycle, regardless of the source of acetyl-CoA.
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

The correct answer is D. There is no difference in the TCA cycle,regardless  of source of acetyl CoA.

Explanation:

Acetyl CoA is the central metabolite of aerobic respiration.Acetyl CoA is generated from both decarboxylation of pyruvate and from the beta oxidation of fatty acid in mitochondrial matrix.

            In both cases the generated Acetyl CoA molecule is same but it comes from different source.

  If the Acetyl CoA generated from beta oxidation of fatty acid enter into the TCA cycle it will generate same molecules of NADP and FADH2 as that of Acetyl CoA generated from carbohydrate metabolism

         

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Likurg_2 [28]

Answer : The mass of nitric acid is, 214.234 grams.

Solution : Given,

Moles of nitric acid = 3.4 moles

Molar mass of nitric acid = 63.01 g/mole

Formula used :

\text{Mass of }HNO_3=\text{Moles of }HNO_3\times \text{Molar mass of }HNO_3

Now put all the given values in this formula, we get the mass of nitric acid.

\text{Mass of }HNO_3=(3.4moles)\times (63..01g/mole)=214.234g

Therefore, the mass of nitric acid is, 214.234 grams.


6 0
3 years ago
Pls helps asap plssss !!!!
DerKrebs [107]

Answer:1 3 4 1 im pretty positive

5 0
3 years ago
Read 2 more answers
When a -COOH group replaces a hydrogen in a hydrocarbon the result is a/an ____.
jonny [76]
Carboxylic acid...........
7 0
3 years ago
10 + 32 -6=any one?​
Kryger [21]

Answer:

Your answer will be 36

Explanation:

10+32=42

42-6=36

3 0
3 years ago
A rigid vessel contains 3.98 kg of refrigerant-134a at 700 kPa and 60°C. Determine the volume of the vessel and the total intern
Arada [10]

<u>Answer:</u> The volume of the vessel is 0.1542m^3 and total internal energy is 162.0 kJ.

<u>Explanation:</u>

  • To calculate the volume of water, we use the equation given by ideal gas, which is:

PV=nRT

or,

PV=\frac{m}{M}RT

where,

P = pressure of container = 700 kPa

V = volume of container = ? L

m = Given mass of R-134a = 3.98 kg = 3980 g    (Conversion factor: 1kg = 1000 g)

M = Molar mass of R-134a = 102.03 g/mol

R = Gas constant = 8.31\text{L kPa }mol^{-1}K^{-1}

T = temperature of container = 60^oC=[60+273]K=333K

Putting values in above equation, we get:

700kPa\times V=\frac{3980g}{102.03g/mol}\times 8.31\text{L kPa }\times 333K\\\\V=154.21L

Converting this value into m^3, we use the conversion factor:

1m^3=1000L

So, \Rightarrow (\frac{1m^3}{1000L})\times 154.21L

\Rightarrow 0.1542m^3

  • To calculate the internal energy, we use the equation:

U=\frac{3}{2}nRT

or,

U=\frac{3}{2}\frac{m}{M}RT

where,

U = total internal energy

m = given mass of R-134a = 3.98 kg = 3980 g  (Conversion factor: 1kg = 1000g)

M = molar mass of R-134a = 102.03 g/mol

R = Gas constant = 8.314J/K.mol

T = temperature = 60^oC=[60+273]K=333K

Putting values in above equation, we get:

U=\frac{3}{2}\times \frac{3980g}{102.03g/mol}\times 8.314J/K.mol\times 333K\\\\U=161994.6J

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, 161994.6 J = 162.0 kJ

Hence, the volume of the vessel is 0.1542m^3 and total internal energy is 162.0 kJ.

6 0
3 years ago
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