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Nady [450]
3 years ago
5

The oxidation of pyruvate is not the only process that generates acetyl-CoA. In particular, fatty acids are broken down through

oxidation, generating a great deal of acetyl-CoA, which can also enter the TCA cycle to generate high energy molecules. Is there a difference between between the TCA cycle using acetyl-CoA generated from fatty acid oxidation compared to that generated from carbohydrate oxidation?
A. The concentration of malate increases when reacting with acetyl-CoA derived from a fatty acid,
B. A molecule of acetyl-CoA derived from a fatty acid generates more FADH2 than acetyl-CoA from
C. A molecule of acetyl-CoA derived from a carbohydrate generates more NADH than acetyl-CoA but not when reacting with acetyl-CoA derived from a carbohydrate. WI derived from a carbohydrate derived from a fatty acid.
D. There is no difference in the TCA cycle, regardless of the source of acetyl-CoA.
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

The correct answer is D. There is no difference in the TCA cycle,regardless  of source of acetyl CoA.

Explanation:

Acetyl CoA is the central metabolite of aerobic respiration.Acetyl CoA is generated from both decarboxylation of pyruvate and from the beta oxidation of fatty acid in mitochondrial matrix.

            In both cases the generated Acetyl CoA molecule is same but it comes from different source.

  If the Acetyl CoA generated from beta oxidation of fatty acid enter into the TCA cycle it will generate same molecules of NADP and FADH2 as that of Acetyl CoA generated from carbohydrate metabolism

         

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Which element is the excess reagent when 3.00 moles of Mg is ignited in 2.20 moles of pure oxygen
Artyom0805 [142]

Answer:

Oxygen is in excess.

Explanation:

The coefficients of the balanced equation create a mole ratio that shows the ratio of how many reactants are used up and products are created.  

The mole ratio of Mg to O2 in this equation is 2:1, which means that for every two moles of Mg used, there will be 1 mole of O2 used.

If we have 3.00 moles of Mg, we will only need 1.5 moles of oxygen to completely burn the Mg. Therefore, when all 3.00 moles of Mg are used, there will still be some of the 2.20 moles of oxygen remaining.

7 0
3 years ago
How can you tell if an element has been oxidized or reduced in a reaction?
fomenos
Gaining of electrons is reduction and loss of electrons is oxidation. 

<em>Hope this helped! :)</em>
7 0
3 years ago
The rate law for the decomposition of phosphine (PH3) is below. It takes 120. s for 1.00 M PH3 to decrease to 0.250 M. How much
Lubov Fominskaja [6]

Answer: 588.8 seconds

Explanation:

1.00 - 0.25 = 0.75M

4.00 - 0.320 = 3.68M

Therefore,

0.75M in 120 seconds

3.68M in x seconds

Cross multiply:

0.75*x = 120*3.68

x = 120*3.68/0.75

x = 588.8 seconds

8 0
3 years ago
What is the value of for this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 kj/mol
sineoko [7]

The value for this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium

<h3>What is an aqueous reaction in equilibrium?</h3>

When a chemical reaction happens at the liquid state and the formation of reactant and product is the same then the reaction is known as an aqueous reaction in equilibrium denoted by K.

δG = − R T ln

          R = universal gas constant 8.313

          δG= 20. 46 kj/mol

           T =  298 k or 24.4 in celcius.

substituting the value in the equation.

20. 46 kj/mol = 8.313 × 24.4 in celcius × K

K =  8.313 × 24.4 in celcius / 20. 46 kj/mo

k = 9.91 mol .

Therefore, The value of this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium

Learn more about the aqueous reaction in  equilibrium, here:

brainly.com/question/8983893

#SPJ4

5 0
2 years ago
Solution A: pH of 10
serious [3.7K]

Answer:

I think it’s C,B,A

Explanation:

5 0
3 years ago
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