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xeze [42]
3 years ago
13

Which chemical is responsible for opening the hair cuticle?

Chemistry
1 answer:
SashulF [63]3 years ago
6 0
Peroxide is the chemical responsible for opening the hair cuticle
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An ionic bond occurs between what particles
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<span>The correct answer is that an ionic bond forms between charged particles. To form this bond, the particles transfer valence electrons (those in the outermost orbit). Specifically, in ionic bonding, the metal atom loses its electrons (thus becoming positive) and the nonmetal atom gains electrons (thus becoming negative).</span>
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QUESTION 3
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Bacteria can’t live without humans
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Please help asap!!!!!!!
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Answer:

A.

Explanation:

Power is measured in Watts, and can we calculated by taking the work done in joules / the time in seconds. Thus, 1 Watt is 1 joule per 1 second (1 Watt = 1J/s)

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2 years ago
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Determine the number of atoms of each element in the empirical formula of a compound with the following composition:
34kurt
To determine the empirical formula of the compound, we assume a basis of 100 g of this compound. We calculate as follows:

C = 68.75 g
H = 10.90 g
O = 20.35 g

We convert these mass to moles,
C = 68.75 g / 12.01 g/mol = 5.72 mol
H = 10.90 g / 1.01 g/mol = 10.79 mol
O = 20.35 g / 16 g/mol = 1.27 mol

C = 5.72 mol / 1.27 mol = 5
H = 10.79 mol / 1.27 mol = 8
O = 1.27 mol / 1.27 mol = 1

C5H8O
6 0
3 years ago
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A solution of permanganate is standardized by titration with oxalic acid, . To react completely with mol of oxalic acid required
Zielflug [23.3K]

Answer:

M=0.120M

Explanation:

Hello,

In this case, the undergone chemical reaction is:

MnO_4^-(aq)+H_2C_2O_4(aq)\rightarrow Mn^{+2}+CO_2

In such a way, the acidic redox balance turns out:

(Mn^{+7}O_4)^-+5e^-+8H^+\rightarrow Mn^{+2}+4H_2O\\H_2C_2O_4\rightarrow2CO_2+2H^++2e^-

Which leads to the total balanced equation as follows:

2(MnO_4)^-(aq)+6H^+(aq)+5H_2C_2O_4(aq)\rightarrow2Mn^{+2}(aq)+8H_2O(l)+10CO_2(g)

Thus, as the mass of oxalic acid is not given, one could suppose a value of 1 g (which you can modify based on the actual statement) in order to compute the oxalic acid moles as shwon below:

1gH_2C_2O_4*\frac{1molH_2C_2O_4}{90.04gH_2C_2O_4} *\frac{2mol(MnO_4)^-}{5molH_2C_2O_4} =0.00444mol(MnO_4)^-

Whereby the molality results:

M=\frac{0.00444mol(MnO_4)^-}{0.03702L} =0.120M

Remember you can modify the oxalic acid mass as you desire.

Best regards.

5 0
3 years ago
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