1) You need to get volume of both temperatures by using first attached formula V= Mass/Density
2) Using the second formula you get the height of 0 degree
(radius in cm is
3) Then with h1 you can easily get the height of 25 degrees
Subtract 943.5 cm - 939.2 cm, and obtain a rise in mercury height of 4.3 cm
I would say D. Hope I helped, sorry if I didn't. :)
The experimental method for measuring the change in concentration with time for the given reaction is by measuring the amount of gas a reaction releases over time.
2NO(g) + Cl₂(g) → 2NOCl(g)
<h3>What is reaction rate?</h3>
- The reaction rate is the rate at which a chemical reaction proceeds.
- Which is proportional to both the increase in a product's concentration per unit time and the decrease in a reactant's concentration per unit time.
- There is a wide range in reaction times.
- The general definition is that the term "rate of a reaction" refers to the pace at which a reaction occurs.
- As an illustration, iron rusting has a low reaction rate since the process is slow but wood burning has a high reaction rate because the process is quick.
Learn more about reaction rate here:
brainly.com/question/13440548
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Explanation:
At 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.
What is an ideal gas equation?
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide
the given mass by the number of moles to get molar mass.
Given data:
P= 0.0721 atm
n=\frac{mass}{molar \;mass}n=
molarmass
mass
R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}R=0.082057338LatmK
−1
mol
−1
T=?
Putting value in the given equation:
\frac{PV}{RT}=n
RT
PV
=n
density = \frac{2 \;atm\; X molar\; mass}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}density=
0.082057338LatmK
−1
mol
−1
XT
2atmXmolarmass
0.260 g/L = \frac{0.0721 \;atm\; X 108.07 g/mol}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}0.260g/L=
0.082057338LatmK
−1
mol
−1
XT
0.0721atmX108.07g/mol
T = 365.2158727 K= 365 K
Hence , at 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.
Answer:
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