I think we need more information
The excess reactant is Aluminum.
<u>Explanation:</u>
We have to write the balanced equation as,
4 Al+ 3 O₂ → 2 Al₂O₃
According to the molar ratio 4: 3, from the given balanced equation, we can say that 4 atoms of Al reacted with 3 molecules of oxygen.
Given that 10 atoms of aluminum reacts with 6 molecules of oxygen, as per the ratio only 8 atoms of Aluminum is required to react with 6 molecules of oxygen, so excess reactant is Aluminum.
Answer:
V₁ = 228 mL
Explanation:
There is some info missing. I think this is the original question.
<em>A chemist must prepare 575 mL of 50.0 mM aqueous potassium permanganate (KMnO₄) working solution. He'll do this by pouring out some 0.126M aqueous potassium permanganate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the potassium permanganate stock solution that the chemist should pour out. Round your answer to 3 significant digits.</em>
<em />
We want to prepare 575 mL (V₂) of a 50.0 mM solution (C₂). To do so, we start, from a stock solution of concentration C₁ = 0.126 M. In order to find the volume V₁ that the chemist should pour out, we will use the dilution rule.
C₁ × V₁ = C₂ × V₂
0.126 M × V₁ = 50.0 mM × 575 mL
0.126 M × V₁ = 50.0 × 10⁻³ M × 575 mL
V₁ = 228 mL
If you don't wash the thermometer, residual NaOH will react with the HCl solution. This is a highly exothermic reaction and will change the temperature of the solution, and thus throw off your measurement.
No hablo espanol could you put it in English?
