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irakobra [83]
4 years ago
8

A slinky forms it’s third harmonic standing wave when the input frequency is 24 Hz. What is the fundamental frequency of the sli

nky? Will an input frequency of 28 Hz create a standing wave? Explain your answer.
Physics
1 answer:
jarptica [38.1K]4 years ago
6 0

Answer: The fundamental frequency of the slinky = 8Hz

An input frequency of 28 Hz will not create a standing wave

Explanation:

Let Fo = fundamental frequency

At third harmonic,

F = 3Fo

If F = 24Hz

24 = 3Fo

Fo = 24/3 = 8Hz

If an input frequency = 28 Hz at 3rd harmonic

Let find the fundamental frequency

28 = 3Fo

Fo = 28/3

Fo = 9.33333Hz

Since Fo isn't a whole number, it can't create a standing wave

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A parking lot is going to be 40 m wide and 100 m long. Which dimensions
dmitriy555 [2]
Answer: A

Explanation: You need to find the dimensions of the scale model of the lot that can be multiplied equally to get the original length. Basically 40 m and 100 m need to be divided by the same number to make the scale model evenly, and right off the bat you see that 10 and 25 could be multiplied by 4 and equal the original numbers. Hope this helps! Also sorry if it was kinda hard to understand lol, when i explain things its hard to get out of my own head ;P
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3 years ago
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Does anyone know how to solve this? 4+9×2÷3−1
Anika [276]

The answer is 7.66. c:

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3 years ago
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When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose anot
gayaneshka [121]

Answer:

The value is E =  1.35 *10^{14} \ J

Explanation:

From the question we are told that

    The mass of matter converted to energy on first test is  m  =  1 \  g  = 0.001 \  kg

    The mass of matter converted to energy on second test m_1 =  1.5 \  g = 1.5 *10^{-3} \ kg

    Generally the amount of energy that was released by  the explosion is  mathematically  represented as  

         E =  m * c^2

=>       E =  1.5 *10^{-3}  * [ 3.0 *10^{8}]^2

=>       E =  1.35 *10^{14} \ J

7 0
3 years ago
Anakin Skywalker's pod racer has a mass of 450 kg. If the top speed of this racer is 947
andriy [413]

Answer:

15,569,653.3 Joules(J)

Explanation:

The equation used to find Kinetic Energy (KE) is

KE = \frac{1}{2} m v^{2}

You have been given

m = 450kg

v = 947km/h

KE = ???

Firstly, we need to convert the km/h into m/s as this is the unit used in the KE equation

This can be done by dividing by 3.6

947km/h = 263.056m/s

Substitute you values into the equation

KE = \frac{1}{2} m v^{2}

KE = \frac{1}{2} * 450 * 263.056^{2}

KE = 15,569,653.3 Joules(J)

Round your answer as appropriate

3 0
3 years ago
A phone cord is 2.28 m long. The cord has a mass of 0.2 kg. A transverse wave pulse is produced by plucking one end of the taut
Debora [2.8K]

The characteristics of the speed of the traveling waves allows to find the result for the tension in the string is:  

         T = 10 N

The speed of a wave on a string is given by the relationship.

      v =\sqrt{\frac{T}{\mu } }

Where   v es the velocty, t is the tension ang μ is the lineal density.

They indicate that the length of the string is L = 2.28 m and the pulse makes 4 trips in a time of t = 0.849 s, since the speed of the pulse in the string is constant, we can use the uniform motion ratio, where the distance traveled e 4 L

           v = \frac{d}{t}  

           v = \frac{4 L}{t}  

           v = \frac{4 \ 2.28 }{0.849}  

            v = 10.7  m / s

Let's find the linear density of the string, which is the length of the mass divided by its mass.

            μ = \frac{m}{L}  

            \mu = \frac{0.2}{2.28}  

            μ = 8.77 10⁻² kg / m

The tension is:

        T = v² μ

Let's calculate

        T = 10.7²  8.77 10⁻²

        T = 1 0 N

In conclusion using the characteristics of the velocity of the traveling waves we can find the result for the tension in the string is:

         T = 10 N

Learn more here:  brainly.com/question/12545155

7 0
3 years ago
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