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koban [17]
3 years ago
15

If the mass of a moving object were quartered, it’s inertia would be

Physics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

Quartered

Explanation:

Because you're a liberal.

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According to Newton’s second law of motion, force equals mass times acceleration (F = ma). Given that a car has a mass of 3,000
jek_recluse [69]

Answer:

B

Explanation:

3000 x 2 = 6000

6 0
4 years ago
Please check my answers!
Alecsey [184]
A.) The higher the altitude, the colder the climate will be

B.) Areas near the equator have warmer climates than areas for form the equator.

D.) Winds that blow inland from oceans or large lakes contain a lot of water vapor that will cause precipitation.

C.) Monsoons.
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3 years ago
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How fast or slow an object is moving and in what direction:
nexus9112 [7]

Answer:

this is called speed

Explanation:

its easy

6 0
1 year ago
A baseball is projected horizontally with an initial speed of 18.1 m/s from a height of 1.85 m. at what horizontal distance will
gtnhenbr [62]
1) The motion of the baseball consists of two separate motions along the horizontal (x) and vertical (y) axis. The position on the two directions at time t is given by:
x(t)=v_0t
y(t)=h- \frac{1}{2}gt^2
where the motion on the x-axis is a uniform motion with constant speed v_0=18.1 m/s, while the motion on the y-axis is a uniformly accelerated motion with constant acceleration g=9.81 m/s^2, and initial height h=1.85 m.

First of all, we can find the time t at which the ball reaches the ground by requiring y(t)=0:
0=h- \frac{1}{2}gt^2
t= \sqrt{ \frac{2h}{g} }= \sqrt{ \frac{2(1.85 m)}{9.81 m/s^2} }=  0.61 s

and if now we substitute this time into the equation for x(t), we find the horizontal distance covered during this time interval, which is the horizontal distance covered by the ball before hitting the ground:
x(t)=v_0 t=(18.1 m/s)(0.61 s)=11.04 m

2) Speed of the ball as it hits the ground
We need to find the components of the velocity on the two directions, at the istant when the ball hits the ground.
On the x-axis, the velocity is the same as the initial one: 
v_x=18.1 m/s
On the y-axis, the velocity is given by
v_y(t)=gt
If we substitute t=0.61 s (the time at which the ball reaches the ground), we find
v_y =gt=(9.81 m/s^2)(0.61 s)=6.0 m/s
And the speed of the ball is the magnitude of the resultant of the two components:
v= \sqrt{v_x^2+v_y^2}= \sqrt{(18.1 m/s)^2+(6.0 m/s)^2}=19.1 m/s
8 0
3 years ago
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The magnitudes of two forces are measured to be 120 ± 5 N and 60 ± 3 N. Find the sum and diff erence of the two magnitudes, givi
Pani-rosa [81]

Answer:

62N

Explanation:

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3 years ago
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